我一直在努力为我的Android应用程序实现一项功能,无论设备指向何处,都能获得设备的行进速度和方向。例如:如果我的Android设备指向北方向,如果我向南方向向后移动,则返回我正在向南移动。
我一直在环顾四周,我想出了使用Location的getBearing()方法的可能性(但是,我不知道这是否能解决我的整个问题)。当我调用getBearing()时,由于某种原因它总是返回0.0。我不知道为什么。这是我的代码:
LocationManager lm;
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_gcm);
setUpUI(findViewById(R.id.LinearLayout1));
isRegged = false;
// GCM startup
gcm = GoogleCloudMessaging.getInstance(this);
context = getApplicationContext();
gps = new GPSTracker(context);
// gps.startListening(context);
// gps.setGpsCall(this);
/*
* Variables to indicate location and device ID
*/
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (gps.getIsGPSTrackingEnabled())
{
longitude = Double.valueOf(gps.getLongitude()).toString();
latitude = Double.valueOf(gps.getLatitude()).toString();
}
deviceID = telephonyManager.getDeviceId();
mSensorManager = (SensorManager) getSystemService(SENSOR_SERVICE);
lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
lm.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, (float) 0.0,
this);
}
这是我获得成功的地方。
@Override
public void onLocationChanged(Location currentLocation)
{
float speed = 0;
float speed_mph = 0;
if (previousLocation != null)
{
float distance = currentLocation.distanceTo(previousLocation);
// time taken (in seconds)
float timeTaken = ((currentLocation.getTime() - previousLocation
.getTime()) / 1000);
// calculate speed
if (timeTaken > 0)
{
speed = getAverageSpeed(distance, timeTaken);
speed_mph = (float) (getAverageSpeed(distance, timeTaken) / 1.6);
}
if (speed >= 0)
{
info_text.setVisibility(View.VISIBLE);
info_text_mph.setVisibility(View.VISIBLE);
DecimalFormat df = new DecimalFormat("#.#");
info_text.setText("Speed: " + df.format(speed) + " " + "km/h");
info_text_mph.setText(" Speed: " + df.format(speed_mph) + " "
+ "mph");
if (speed >= 10 && lm.getProvider(LocationManager.GPS_PROVIDER).supportsBearing())
{
float degree = currentLocation.getBearing();
direction_text.setVisibility(View.VISIBLE);
Log.i(TAG, String.valueOf(degree));
if (degree == 0 && degree < 45 || degree >= 315
&& degree == 360)
{
direction_text.setText("You are: Northbound");
}
if (degree >= 45 && degree < 90)
{
direction_text.setText("You are: NorthEastbound");
}
if (degree >= 90 && degree < 135)
{
direction_text.setText("You are: Eastbound");
}
if (degree >= 135 && degree < 180)
{
direction_text.setText("You are: SouthEastbound");
}
if (degree >= 180 && degree < 225)
{
direction_text.setText("You are: SouthWestbound");
}
if (degree >= 225 && degree < 270)
{
direction_text.setText("You are: Westbound");
}
if (degree >= 270 && degree < 315)
{
direction_text.setText("You are: NorthWestbound");
}
}
}
}
previousLocation = currentLocation;
}
非常感谢!
答案 0 :(得分:4)
getBearing()
获取数据, LocationManager.NETWORK_PROVIDER
将返回0,因为信号/准确度太弱。尝试将GPS提供商设置为GPS,并确保在室外进行测试(由于卫星没有直接通信,GPS无法在室内或高层建筑物中间工作)
为了确保您选择的提供商支持getBearing(),您可以使用名为LocationProvider
的{{1}}方法,如果您选择的提供商支持supportsBearing ()
来电,则返回true。 / p>
最后确保您在AndroidManifest.xml中拥有getBearing()
或ACCESS_COARSE_LOCATION
权限
根据我的建议编码将是这样的:
ACCESS_FINE_LOCATION
资源: http://developer.android.com/reference/android/location/LocationManager.html http://developer.android.com/reference/android/location/LocationProvider.html http://www.firstdroid.com/2010/04/29/android-development-using-gps-to-get-current-location-2/
更新:答案是在getBearing()中用于计算的两个点太接近,因此给出了不准确的结果。要纠正此问题,请手动抓取两个GPS点并使用bearingTo()来查看更准确的结果。