我有2个列表框(它们是连接的,因此项目可以从一个移动到另一个),最后我想通过使用“确定”按钮获取第二个列表框中的所有条目(或者只是关闭帧)。每次选择一个项目时,我都可以在列表中添加/删除值(如下面代码的注释部分所示),但我宁愿在<head>
的{{1}}行中添加一行代码。 1}}功能,但我无法使其正常工作。
代码:
[master.selected.get(idx) for idx in master.selected.curselection()]
我试图在关闭函数中使用以下小片段:
close
但是,def measurementPopup(self,master):
self.chargeCarrier = StringVar()
self.massModifiers = StringVar()
self.chargeCarrier.set("[M+xH]")
def onselect1(evt):
w = evt.widget
index = int(w.curselection()[0])
value = w.get(index)
# My Dirty fix -> Here I could enter the selected value to a buffer list (to be returned in the ok function).
master.selected.insert(END,value)
master.avail.delete(index)
def onselect2(evt):
w = evt.widget
index = int(w.curselection()[0])
value = w.get(index)
# My Dirty fix -> Here I could remove the selected value from a buffer list (to be returned in the ok function).
master.selected.delete(index)
master.avail.insert(END,value)
def close(self):
# Here I would return the buffer list and close the window
master.measurementWindow = 0
top.destroy()
if master.measurementWindow == 1:
return
master.measurementWindow = 1
top = self.top = Toplevel()
top.protocol( "WM_DELETE_WINDOW", lambda: close(self))
self.charge = Label(top, text = "Charge", width = 10)
self.charge.grid(row = 0, column = 0, sticky = W)
self.min = Label(top, text = "Min", width = 5)
self.min.grid(row=0, column = 1, sticky = W)
self.minCharge = Spinbox(top, from_= 1, to = 3, width = 5)
self.minCharge.grid(row = 0, column = 2, sticky = W)
self.max = Label(top, text = "Max", width = 5)
self.max.grid(row = 0, column = 3, sticky = W)
self.maxCharge = Spinbox(top, from_ = 1, to=3, width=5)
self.maxCharge.grid(row = 0, column = 4, sticky = W)
self.chargeCarrier = OptionMenu(top, self.chargeCarrier, "[M+xH]", "[M+xNa]")
self.chargeCarrier.grid(row = 0, column = 5, sticky = W)
self.availMass = Label(top, text = "Available")
self.availMass.grid(row = 1, column = 1, sticky = W)
self.selectMass = Label(top, text = "Selected")
self.selectMass.grid(row = 1, column = 3, sticky = W)
self.massMod = Label(top, text = "Mass Mods")
self.massMod.grid(row = 2, column = 0, sticky = W)
self.avail = Listbox(top)
for i in UNITS:
if BLOCKS[i]['available'] == 1:
self.avail.insert(END,BLOCKS[i]['human_readable_name'])
self.avail.grid(row = 2, column = 1, columnspan = 2, sticky = W)
self.avail.bind('<<ListboxSelect>>',onselect1)
self.selected = Listbox(top)
self.selected.grid(row = 2, column = 3, columnspan = 2, sticky = W)
self.selected.bind('<<ListboxSelect>>',onselect2)
self.ok = Button(top,text = 'Ok',command = lambda: close(self))
self.ok.grid(row = 3, column = 0, sticky = W)
细分不返回任何内容。我希望这是因为实际上没有选择任何东西,但我需要一些相反的东西,沿着 values = [master.selected.get(idx) for idx in master.selected.curselection()]
print ', '.join(values)
(如果它存在并且如果我理解正确的话)。
摘要
如何获得1个特定列表框中的所有项目?
答案 0 :(得分:3)
.get()
窗口小部件的Listbox
函数允许您指定一系列项目,可以指定为0
到END
以返回所有项目的元组项目。
示例:
from Tkinter import *
root = Tk()
l = Listbox(root, width = 15)
l.pack()
l.insert(END, "Hello")
l.insert(END, "world")
l.insert(END, "here")
l.insert(END, "is")
l.insert(END, "an")
l.insert(END, "example")
def close():
global l, root
items = l.get(0, END)
print(items)
root.destroy()
b = Button(root, text = "OK", command = close).pack()
root.mainloop()
我希望这有帮助,如果它不是你想要的,请在评论中告诉我,我可以尝试扩展我的答案。