Question

我在论坛上提到了这个问题： Using a string as a variable at run time

这就是我所拥有的：

def create_account
  puts "Username?"
  account_name=gets.chomp
  account_name_var=#account_name as variable

  #Sets array as variable
  string_values = { }
  some_string = [:some_string]       # parameter was, say "Hello"
  string_values[some_string] = account_name
  string_values                            # { 'Hello' => 42 }
  account_name_var = string_values[some_string]
  account_name_var                              # 42

  account_name_var=BankAccount.new(account_name, "open")
  account_name_var=BankAccount.new(account_name, "open")
end

create_account
create_account
# pablo=BankAccount.new("pablo", "open")
# theo=BankAccount.new("theo", "open")
make_transfer(name, name2, 10)

但是我得到了

：main：Object的未定义局部变量或方法名称 make_transfer（name，name2,10）
行上的（NameError）

当我输入name作为第一个用户名并name作为第二个用户名时，name2未设置为变量。

Answer 1

只需从您的方法返回BankAccount实例并将其分配给变量：

def create_account
  puts "Username?"
  account_name = gets.chomp
  BankAccount.new(account_name, "open")
end

account_1 = create_account
account_2 = create_account
make_transfer(account_1, account_2, 10)

或者，使用Hash按名称存储帐户：

@accounts = {}

account = create_account
@accounts[account.name] = account

account = create_account
@accounts[account.name] = account

make_transfer(@accounts['pablo'], @accounts['theo'], 10)

为什么我不能将输入的字符串转换为变量

1 个答案: