Question

我想用post方法设置“application / x-www-form-urlencoded” 所以，我设置request.requestSerializer.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")但是当我将请求设置到服务器时，Content-Type不会改变发生的事情？

这是错误

{com.alamofire.serialization.response.error.response=<NSHTTPURLResponse: 0x7c166450> { URL: http://test.com } { status code: 404, headers {
    Connection = "keep-alive";
    "Content-Length" = 434;
    "Content-Type" = "text/html";
    Date = "Mon, 13 Jul 2015 11:18:18 GMT";
    Server = "nginx/1.0.15";
} }, NSErrorFailingURLKey=http://text.com, NSLocalizedDescription=Request failed: not found (404),

这是我的代码：

var request = AFHTTPRequestOperationManager();
request.requestSerializer = AFHTTPRequestSerializer()
request.requestSerializer.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")

request.POST(url, parameters: parameters, success: { (oper,obj) -> Void in
    // do something
}) { (oper, error) -> Void in
   // do something with error
}

Answer 1

这正是错误所说的：当您期待JSON时，您的服务器正在为400状态代码发回一个网页（HTML）。

400状态代码用于错误请求，这可能是因为您将URL格式编码的文本作为application / json发送而生成的。你真正想要的是将AFJSONRequestSerializer用于你的请求序列化器。

manager.requestSerializer = [AFJSONRequestSerializer serializer];

我没有在Swift中执行任何AFNetworking代码，所以我不能告诉你这些代码，但你可以从objective-c代码中获得想法。

我希望它会对你有所帮助。

Answer 2

试试这个

    let strURL = "Your URL"
    let dictParam : NSDictionary = [
        "u":"b",
        "p":"1290",
        ]

    let manager = AFHTTPSessionManager.init()
    manager.requestSerializer.setValue("content-type", forHTTPHeaderField: "application/x-www-form-urlencoded")
    manager.post(strURL, parameters: dictParam, progress: nil, success: { (task, responseObject) in

        print(responseObject ?? "")

    }, failure: { (task, error) in

        print(error.localizedDescription)
    })

如何在AFNetworking中设置Content-Type？

2 个答案: