Question

我需要找到员工的周年纪念日和周年纪念日，并且每隔14天发送一次电子邮件。但是如果开始日期和结束日期在不同年份，我使用以下查询时会遇到12月最后一周的问题。

    Select * from Resource
    where (DATEPART(dayofyear,JoinDate)
    BETWEEN DATEPART(dayofyear,GETDATE())
    AND DATEPART(dayofyear,DateAdd(DAY,14,GETDATE())))

Answer 1

您可以更新员工{{1>而不是与dayofyear（在1月1日重置为零并且是您的查询在年终的14天内中断的原因）进行比较。为了查询的目的而成为当前年份，只是与实际日期进行比较

joindate

测试查询：

Select * from Resource
-- Add the number of years difference between joinDate and the current year
where DATEADD(year,DATEDIFF(Year,joinDate,GetDate()),JoinDate) 
-- compare to range "today"
BETWEEN GetDate()
-- to 14 days from today
AND DATEADD(Day,14,GetDate())
-- duplicate for following year
OR DATEADD(year,DATEDIFF(Year,joinDate,GetDate())+1,JoinDate) -- 2016-1-1
BETWEEN GetDate() 
AND DATEADD(Day,14,GetDate())

（H / T @Damien_The_Unbeliever进行简单修复）

以上正确选择了1月第一周的declare @joindate DATETIME='2012-1-1' declare @today DATETIME = '2015-12-26' SELECT @joinDate where DATEADD(year,DATEDIFF(Year,@joinDate,@today),@JoinDate) -- 2015-1-1 BETWEEN @today -- 2015-12-26 AND DATEADD(Day,14,@today) -- 2016-01-09 OR DATEADD(year,DATEDIFF(Year,@joinDate,@today)+1,@JoinDate) -- 2016-1-1 BETWEEN @today -- 2015-12-26 AND DATEADD(Day,14,@today) -- 2016-01-09（请注意我已经不得不捏造joinDate，因为我没有设法创造时间旅行。）

上述解决方案还应解决隐藏在原始解决方案中的闰年问题。

<强>更新

您在评论中表达了选择@today和AnniversaryDate服务的要求，您需要应用一些Years逻辑来确定是否为您的选择添加1（年份或日期）

CASE

Answer 2

你可以这样做：

Select * from Resource
where DATEPART(dayofyear,JoinDate)
BETWEEN DATEPART(dayofyear,GETDATE())
AND DATEPART(dayofyear,DateAdd(DAY,14,GETDATE()))
OR
DATEPART(dayofyear,JoinDate)
BETWEEN (DATEPART(dayofyear,GETDATE()) + 365)
AND  (DATEPART(dayofyear,DateAdd(DAY,14,GETDATE())) + 365)

Answer 3

试试这个：

DECLARE @Today DATE = GETDATE() --'12/25/2013'
DECLARE @Duration INT = 14

;WITH Recur AS
(
    SELECT @Today AS RecurDate
    UNION ALL
    SELECT DATEADD(DAY, 1, RecurDate)
    FROM Recur
    WHERE DATEDIFF(DAY, @Today, RecurDate)+1 < @Duration
)
SELECT
    r.*
FROM
    Resource r
    JOIN Recur 
        ON CONVERT(VARCHAR(5), JoinDate, 101) = CONVERT(VARCHAR(5), RecurDate, 101)
WHERE JoinDate <  @Today

Answer 4

您可以将SQL DATEADD() function与周数参数一起使用以下是如何使用它：

DECLARE @date date = getdate()
Select * from Resource
where
    JoinDate BETWEEN @date AND DATEADD(ww,2,@date)

查询员工周年纪念的SQL查询

4 个答案: