Question

这是我的功能，我从数据库中获取结果

function Prof_Viewer($MemberId)
{
   $query = $this->db->query("SELECT distinct(t1.dProfileId) as prof
   FROM tbl_profile_viewer as t1
   JOIN tbl_login as t2
   WHERE t1.dProfileViwerId='$MemberId'");
if($query->num_rows > 0)
  {
    foreach($query->result() as $row)
     {
       echo  $row->prof;//i am receiving many values here
        $query1 = $this->db->query("SELECT distinct(t3.dUser_name),t2.dPath,t3.dCreatedDate
                                      FROM tbl_login as t3
                                      JOIN tbl_profile_viewer as t1,
                                      tbl_member_details as t2
                                       WHERE t3.dMember_Id = '$row->prof'
                                      AND t2.dMember_Id ='$row->prof'");
     }
      return $query1->result_array();
  }
}

如上所述，我收到许多值，同时回显变量$ row-＆gt; prof; 说我有1 2和3等值...... 即使我有这三个值，我'query1'只取最后一个值。所以我只有一个结果我希望查询执行1和2也如何实现

Answer 1

您可以使用PHP explode（）将字符串转换为数组。例如：

<?php
$str = 'one|two|three|four';

// positive limit
print_r(explode('|', $str));

// gives you an array:

Array
(
    [0] => one
    [1] => two
    [2] => three
    [3] => four
)

?>

但我认为如果你学会了如何做JOIN会更好：

http://en.wikipedia.org/wiki/Join_(SQL)

Answer 2

我假设你在这里使用mysqli Result_fetch_array（）将执行您想要的操作 http://au2.php.net/manual/en/mysqli-result.fetch-array.php

如何使用数组中的值获取查询结果？

2 个答案: