Question

我正在尝试获取PLSQL语句以显示所有客户ID列表以及每个客户的订单值总和。下面的代码得到了正确的答案，但问题是我有多个客户具有相同的ID，我需要在1 ID输出下汇总所有订单值而不是multiple.my代码为同一客户获取多个输出。

  Create table sales (customer_ID number(10), product_ID number(10), quantity number(10));

INSERT INTO sales (customer_ID, product_ID, quantity) Values(3,1,23);
INSERT INTO sales (customer_ID, product_ID, quantity) Values(1,2,34);
INSERT INTO sales (customer_ID, product_ID, quantity) Values(1,3,654);
INSERT INTO sales (customer_ID, product_ID, quantity) Values(3,7,32);
INSERT INTO sales (customer_ID, product_ID, quantity) Values(4,3,23);
INSERT INTO sales (customer_ID, product_ID, quantity) Values(3,3,111);
INSERT INTO sales (customer_ID, product_ID, quantity) Values(5,4,6);




Create table products (product_ID number(10), price number(10));
INSERT INTO products (product_ID, price) Values(1,32);
INSERT INTO products (product_ID, price) Values(2,121);
INSERT INTO products (product_ID, price) Values(3,3000);
INSERT INTO products (product_ID, price) Values(4,621);
INSERT INTO products (product_ID, price) Values(5,363);
INSERT INTO products (product_ID, price) Values(6,32);
INSERT INTO products (product_ID, price) Values(7,3);
INSERT INTO products (product_ID, price) Values(8,432);
INSERT INTO products (product_ID, price) Values(9,11);
INSERT INTO products (product_ID, price) Values(10,73);


declare
cursor cur is select unique sales.quantity,products.price,sales.customer_ID
from sales,products
where sales.product_id=products.product_id
order by customer_ID desc;
prod number;
quan number(10);
pri number(10);
c_id number(10);
begin
open cur;
loop
fetch cur into quan,pri,c_id;
exit when cur%notfound;
prod:=pri*quan;
DBMS_OUTPUT.PUT_LINE('customer_id =' || c_id);
DBMS_OUTPUT.PUT_LINE('quantity value =' || quan);
DBMS_OUTPUT.PUT_LINE('price =' || pri);
DBMS_OUTPUT.PUT_LINE('The total value of customer purchases is = ' || prod);
end loop;
close cur;
END

请adivse。

Answer 1

试试这个

SELECT CUSTOMER_ID
     ,SUM(QUANTITY) as Total_Quantity
     ,SUM(QUANTITY*PRICE) as Total_Price
FROM
SALES s INNER JOIN
PRODUCTS p on p.PRODUCT_ID=s.PRODUCT_ID
GROUP BY CUSTOMER_ID   // Group By each customer Id.

Answer 2

您只需使用 SUM 作为聚合函数 GROUP BY 。

使用 PL / SQL

SQL> SET serveroutput ON
SQL> DECLARE
  2    CURSOR cur
  3    IS
  4      SELECT SUM(sales.quantity),
  5        SUM(products.price),
  6        sales.customer_ID
  7      FROM sales,
  8        products
  9      WHERE sales.product_id=products.product_id
 10      GROUP BY customer_ID
 11      ORDER BY customer_ID DESC;
 12    prod NUMBER;
 13    quan NUMBER(10);
 14    pri  NUMBER(10);
 15    c_id NUMBER(10);
 16  BEGIN
 17    OPEN cur;
 18    LOOP
 19      FETCH cur INTO quan,pri,c_id;
 20      EXIT
 21    WHEN cur%notfound;
 22      prod:=pri*quan;
 23      DBMS_OUTPUT.PUT_LINE('customer_id =' || c_id);
 24      DBMS_OUTPUT.PUT_LINE('quantity value =' || quan);
 25      DBMS_OUTPUT.PUT_LINE('price =' || pri);
 26      DBMS_OUTPUT.PUT_LINE('The total value of customer purchases is = ' || prod);
 27    END LOOP;
 28    CLOSE cur;
 29  END;
 30  /
customer_id =5
quantity value =6
price =621
The total value of customer purchases is = 3726
customer_id =4
quantity value =23
price =3000
The total value of customer purchases is = 69000
customer_id =3
quantity value =166
price =3035
The total value of customer purchases is = 503810
customer_id =1
quantity value =688
price =3121
The total value of customer purchases is = 2147248

PL/SQL procedure successfully completed.

SQL>

顺便说一下，整个 PL / SQL 块可以用纯 SQL 编写。

使用 SQL

SQL> SELECT SUM(sales.quantity) AS "quantity",
  2    SUM(products.price) AS "price",
  3    sales.customer_ID
  4  FROM sales,
  5    products
  6  WHERE sales.product_id=products.product_id
  7  GROUP BY customer_ID
  8  ORDER BY customer_ID DESC;

  quantity      price CUSTOMER_ID
---------- ---------- -----------
         6        621           5
        23       3000           4
       166       3035           3
       688       3121           1

SQL>

更新 OP希望根据用户输入过滤行。

在 SQL * Plus 中，您可以声明一个变量并在过滤谓词中使用它：

SQL> variable cust_id NUMBER
SQL> EXEC :cust_id:= 4

PL/SQL procedure successfully completed.

不，让我们在过滤谓词中使用上面的变量：

SQL> SET serveroutput ON
SQL> DECLARE
  2    CURSOR cur
  3    IS
  4      SELECT SUM(sales.quantity),
  5        SUM(products.price),
  6        sales.customer_ID
  7      FROM sales,
  8        products
  9      WHERE sales.product_id=products.product_id
 10      AND sales.customer_ID = :cust_id
 11      GROUP BY customer_ID
 12      ORDER BY customer_ID DESC;
 13    prod NUMBER;
 14    quan NUMBER(10);
 15    pri  NUMBER(10);
 16    c_id NUMBER(10);
 17  BEGIN
 18    OPEN cur;
 19    LOOP
 20      FETCH cur INTO quan,pri,c_id;
 21      EXIT
 22    WHEN cur%notfound;
 23      prod:=pri*quan;
 24      DBMS_OUTPUT.PUT_LINE('customer_id =' || c_id);
 25      DBMS_OUTPUT.PUT_LINE('quantity value =' || quan);
 26      DBMS_OUTPUT.PUT_LINE('price =' || pri);
 27      DBMS_OUTPUT.PUT_LINE('The total value of customer purchases is = ' || prod);
 28    END LOOP;
 29    CLOSE cur;
 30  END;
 31  /
customer_id =4
quantity value =23
price =3000
The total value of customer purchases is = 69000

PL/SQL procedure successfully completed.

SQL>

如果您想从前端应用程序执行此操作，可以将整个逻辑放在 PROCEDURE 中并接受customer_id作为 IN参数 。并在过滤谓词中使用它。

Answer 3

您可以使用sum（）函数，例如select sum（sales.quantity）而不是sales-quantity。这将为您提供该customer_id的总数量

Answer 4

DECLARE

//声明变量

a   NUMBER;
b  NUMBER;
Cal NUMBER;

PROCEDURE calcul (a IN NUMBER,b     IN NUMBER,Cal   OUT NUMBER)IS

//检查IF条件是否等于b，那么它将添加a和B. BEGIN

        IF a <> b THEN
            Cal := a + b;
        END IF;
  END;

//将值传递给a和b然后调用calcul过程将进行添加。

   BEGIN
    a := 10;
    b := 15;
    calcul(a,b,Cal);
    dbms_output.put_line('Sum is ' || Cal);
   END;

总值的总和PL / Sql

4 个答案: