这是我的ajax:
$("#submit").on("click",function()
{
$("#add_car_form").submit(function(){
var data = {
"action": "test"
};
data = $(this).serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "text",
url: "add_car_submit.php", //Relative or absolute path to response.php file
data: data,
success: function(data) {
$(".the-return").html("<br />JSON: " + data );//this outputs
{ “car_name”: “; 11”, “car_maker”: “NJK”, “car_type”: “NKJ”, “通勤”: “1”, “速率”:[ “89”, “67”, “45”, “34”, “23”], “动作”: “测试”}
}
});
document.getElementById("add_car_form").reset();
return false;
});
});
我只是回复来自php脚本:echo $return["json"];
,它将输出如下:
{"car_name":";ll","car_maker":"njk","car_type":"nkj","passanger":"1","rate":["89","67","45","34","23"],"action":"test"}
如何在html表格中附加这样的div?
Car Name: name
Car Maker: maker
......
答案 0 :(得分:1)
您不应在点击处理程序中创建表单提交处理程序,因为它可以为单击事件创建多个侦听器。
我认为您可以在服务器端使用json_encode
对数据进行编码,然后使用json
接受客户端中的dataType: 'json'
响应,然后
$("#submit").on("click", function () {
var $form = $("#add_car_form")
var data = {
"action": "test"
};
data = $form.serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "add_car_submit.php", //Relative or absolute path to response.php file
data: data,
success: function (data) {
$(".the-return").html("Car Name" + data.car_name + '<br />Car Maker' + data.car_maker); //Add more properties here
}
});
document.getElementById("add_car_form").reset();
return false;
});
答案 1 :(得分:1)
在你的成功函数中尝试这个
data = jQuery.parseJSON( data ); //parse data if this is text other wise use data directly. hope this is a text param in your case.
var out = '<table>';
$.each(data, function( key, value ) {
out += '<tr><td>'+key+': '+ value +'</td></tr>';
});
out += '</table>';
//append out to your div
$(".the-return").html(out);