Question

我是Play框架的新手。我试图在示例后编译我的play框架项目。当我编译示例时，它工作正常，并在目标中将.scala.html视图编译为.class。我添加了一个新视图，但它没有编译到目标中。有任何建议如何解决这个问题？我尝试使用命令行进行激活器编译，清理并重新构建项目，单独构建.scala.html，但没有尝试过。如何在Play 2.4中添加新视图并进行编译？

package controllers;

import models.Client; 
import models.Server;
import models.TestEvent;
import models.TestPlan;

import play.data.Form;
import play.mvc.Controller;
import play.mvc.Result;
import views.formData.testFormData;

public class Application extends Controller {

// Default path request
// public Result index() {return ok(index.render("Your new application is ready."));}


/* Index Route Page
 * Returns the page where the form is filled with the arguments passed
 * Or an empty form if the id is 0
 */
public static Result getIndex(long id) {
    testFormData testData;
    // Find the corresponding index result to return (depends on the id)
    if(id == 0)
        testData = new testFormData();
    else
        testData = models.TestEvent.makeTestFormData(id);

    Form<testFormData> formData = Form.form(testFormData.class).fill(testData);
    return ok(index.render(formData,
            Client.getClientNameList(),
            Server.getServerNameList(),
            TestPlan.getTestPlanNameList()));
}


// Process a form submission
// Bind HTTP Post data to an instance of testFormData
// If errors are found, re-render the page displaying the error data
// If errors are not found, re-render the page displaying good data
public static Result postIndex() {
    // Retrieve the formData
    Form<testFormData> formData = Form.form(testFormData.class).bindFromRequest();

    // The retrieved formData has errors
    if(formData.hasErrors()) {
        return badRequest(index.render(formData,
                Client.getClientNameList(),
                Server.getServerNameList(),
                TestPlan.getTestPlanNameList()));
    }

    // The formData does not have errors
    else {
        // Convert the form data into a testEvent Instance
        TestEvent testEvent = TestEvent.makeTestEventInstance(formData.get());

        return ok(index.render(formData,
                Client.getClientNameList(),
                Server.getServerNameList(),
                TestPlan.getTestPlanNameList()));
    }
}
}

路线：

GET     /                           controllers.Application.getIndex(id:Long ?= 0)

 POST    /                           controllers.Application.postIndex()



 # Map static resources from the /public folder to the /assets URL path
 GET     /assets/*file               controllers.Assets.versioned(path="/public", file: Asset)

Answer 1

如果服务器在您编码时没有运行，则无法编译更改。您可以通过打开连续编译功能来解决此问题，每次将更改写入文件系统时都会进行编译。

要做到这一点：

启动激活器
使用~compile

~表示应立即编译更改。

您可以对服务器执行类似操作。通过使用~run，将在文件系统更改时立即编译更改，并且在浏览器刷新之前不会延迟更改。

新视图.scala.html到.class的编译问题

1 个答案: