如何将浮动转换为列表。 （蟒蛇）

Question

我需要将浮动变成列表。 （Python 2.7.10） 例如

float = 7.434

list = [7, ".", 4, 3, 4]

我需要这个，所以我可以迭代浮动。

Answer 1

如果 有列表：

list(int(i) if i.isdigit() else i for i in str(7.345))

但你可以迭代一个字符串

for i in str(-7.345): print i
-
7
.
3
4
5

（请注意，所有这些都是字符串...）

Answer 2

[int(i) if i.isdigit() else i for i in map(str, str(number))]

示例：

>>> num = 1.2345
>>> [int(i) if i.isdigit() else i for i in map(str, str(num))]
[1, '.', 2, 3, 4, 5]
>>> num = -1.2345
>>> [int(i) if i.isdigit() else i for i in map(str, str(num))]
['-', 1, '.', 2, 3, 4, 5]

Answer 3

只需list = list(str(float))。

Answer 4

我希望这是有用的：D

#You have a float like this :` float = 7.434`
#Now ,  let's convert the "float" variable to a list:

float=7.434
LIST=[]
float_to_str=str(float)
for elem in float_to_str:
    #In elem is a dot ( . ) :
    if elem==".":
        LIST.append(elem)
    else:
        #If the element is a number:
        LIST.append( int(elem) )



#    In case you want to see you list : 
print(str(LIST))

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