例如，我希望程序在有人按下＆＃34之后不停地运行多次;请点击完成流程＆＃34;。但是，当我再次运行GUI方法时，只显示第一个面板。不确定为什么会这样。
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import javax.swing.*;
public class Hotel {
public static JFrame frame;
public static JPanel pan;
public static JPanel endPanel;
public static JPanel buttonPanel;
public static GridBagConstraints c;
public static GridBagConstraints f;
public static JButton econ;
public static Boolean openA = true;
public Hotel(){
Frame();
GUI();
}
public static void Frame(){
frame = new JFrame ("Kiosk");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setVisible(true);
frame.setSize(600,400);
}
public static void GUI (){
pan = new JPanel(new GridBagLayout());
c = new GridBagConstraints();
frame.add(pan);
JLabel l2 = new JLabel("Please fill out your name and room number");
l2.setVisible(false);
pan.add(l2);
buttonPanel = new JPanel(new GridBagLayout());
GridBagConstraints GB = new GridBagConstraints();
JButton b1 = new JButton("Check in?");
c.gridx=0;
c.gridy=0;
c.insets = new Insets(10,10,10,10);
buttonPanel.add(b1, c);
JButton b2 = new JButton("Check out?");
c.gridx=1;
c.gridy=0;
c.insets = new Insets(10,10,10,10);
buttonPanel.add(b2, c);
frame.add(buttonPanel);
b1.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e)
{
buttonPanel.setVisible(false);
Checkin();
}
});
b2.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e)
{
l2.setVisible(true);
b1.setVisible(false);
b2.setVisible(false);
}
});
}
public static void Checkin(){
JLabel name = new JLabel("What is your name?");
c.gridx=0;
c.gridy=0;
pan.add(name,c);
JLabel number = new JLabel("How many people in your party?");
c.gridx=0;
c.gridy=3;
pan.add(number,c);
JTextField namefield = new JTextField(20);
c.insets = new Insets(10,10,10,10);
c.gridx=1;
c.gridy=0;
pan.add(namefield,c);
JTextField numberfield = new JTextField(2);
c.insets = new Insets(10,10,10,10);
c.gridx=1;
c.gridy=3;
pan.add(numberfield,c);
JButton confirm = new JButton("Confirm");
c.insets = new Insets(10,10,10,10);
c.gridx=1;
c.gridy=4;
pan.add(confirm,c);
JPanel errorPanel = new JPanel(new GridBagLayout());
GridBagConstraints d = new GridBagConstraints();
errorPanel.setVisible(false);
frame.add(errorPanel);
JButton econ = new JButton("Confirm");
d.insets = new Insets(10,10,10,10);
d.gridx=1;
d.gridy=4;
errorPanel.add(econ,d);
JLabel error = new JLabel("Sorry you must fill in all the fields");
d.insets = new Insets(10,10,10,10);
d.gridx=1;
d.gridy=0;
errorPanel.add(error,d);
confirm.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent e){
if((namefield.getText().equals("")) ||
(numberfield.getText().equals(""))){
pan.setVisible(false);
errorPanel.setVisible(true);
econ.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent e){
errorPanel.setVisible(false);
pan.setVisible(true);
}
});
}
else{
endPanel = new JPanel(new GridBagLayout());
f = new GridBagConstraints();
pan.setVisible(false);
frame.add(endPanel);
String hey = namefield.getText();
Memory(hey);
int people =0;
try {
people = Integer.parseInt(numberfield.getText());
}
catch(NumberFormatException ex)
{
System.out.println("Exception : "+ex);
}
Rooms(people);
}
}
});
}
public static void Memory(String h){
ArrayList<String> Guest = new ArrayList<String>();
for(int x=0;x<Guest.size();x++){
if(Guest.get(x).equals(h)){
JLabel duplicate = new JLabel("Duplicate Name - Please refer
to the manager " + h);
JPanel dupPanel = new JPanel();
pan.setVisible(false);
dupPanel.setVisible(true);
frame.add(dupPanel);
econ.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent e){
dupPanel.setVisible(false);
pan.setVisible(true);
}
});
}
else{
JLabel nameLab = new JLabel("Have a nice day " + h);
f.insets = new Insets(10,10,10,10);
f.gridx = 0;
f.gridy=0;
endPanel.add(nameLab);
}
Guest.add(h);
}
}
public static void Rooms(Integer n){
JLabel roomLab = new JLabel("Sorry there are no rooms with that
occupany available");
f.insets = new Insets(10,10,10,10);
f.gridx = 0;
f.gridy=0;
endPanel.add(roomLab,f);
JButton restart = new JButton("Please hit to finish process");
f.insets = new Insets(10,10,10,10);
f.gridx = 0;
f.gridy=4;
endPanel.add(restart,f);
int x=0;
if(openA == true && n<2){
openA = false;
x=1;
}
switch(x){
case 1 : roomLab.setText("You have been assigned room A");
}
restart.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent e){
endPanel.setVisible(false);
GUI();
}
});
}
public static void main(String[] args) {
new Hotel();
}
}
答案 0 :(得分：-1)
如果要干净地重新启动GUI，并确保新GUI与前一个GUI完全独立，最好的办法是丢弃前一个GUI，并创建一个全新的实例。
您的案例中最大的问题是您的所有字段和方法都是静态的。这是错的。你通常应该有：
public class Hotel extends JFrame {
public JPanel pan;
...
public Hotel() {
super("Kiosk");
createGUI();
setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
setVisible(true);
setSize(600,400);
}
public void createGUI(){
pan = new JPanel(new GridBagLayout());
c = new GridBagConstraints();
add(pan);
...
如果您想重新启动GUI，那么非常简单：
restart.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent e){
dispose();
new Hotel();
}
});
如果您只想重置框架中的特定面板，可以将其从容器中移除，然后添加新实例：
somepanel.remove(somesubpanel);
somepanel.add(createSubpanel());