Question

如何找到工作时间最少的员工并显示他们的姓名和工作总时数？

我似乎无法弄清楚如何显示名称（即员工2，员工3等），最少工作小时数总是等于零。

import javax.swing.JOptionPane;

public class EmpHrsWrkd {
   public static void main(String[] args) {
      String[] employees =
         {
         "Employee 1",
         "Employee 2",
         "Employee 3",
         "Employee 4",
         "Employee 5",
         "Employee 6",
         };

      int[][] hrsWrkd =
         {
         { 5, 8, 6, 2 },
         { 2, 0, 8, 6 },
         { 6, 4, 9, 5 },
         { 7, 8, 8, 4 },
         { 3, 6, 2, 8 },
         { 9, 5, 1, 7 },
         };

    // Calculate the rows and columns in 2D array
      final int EMPLOYEES = hrsWrkd.length;
      final int HOURS = hrsWrkd[0].length;

      // Find employee that worked least number of hours
      int min = hrsWrkd[0][0];
      for (int col = 0; col < hrsWrkd.length; col++) {
         for (int row = 0; row < hrsWrkd[col].length; row++) { 
            if (min > hrsWrkd[col][row]) {
               min = hrsWrkd[col][row];
            }
         }
      }
      JOptionPane.showMessageDialog(null, min);
   }
}

Answer 1

因此，在您的代码中，您要比较每个员工的单个小时而不是它的总和。它始终为0，因为矩阵中的最小数字是0.

要做到这一点，首先必须为每位员工计算小时数，然后将其进行比较以获得验证结果。如下图所示：

    int minValue = Integer.MAX_VALUE;
    int employeeWithMinValue = -1;
    for (int col = 0; col < hrsWrkd.length; col++) {
        int tempSum = 0;
        for (int row = 0; row < hrsWrkd[col].length; row++) {
            tempSum = tempSum + hrsWrkd[col][row];
        }
        if (tempSum < minValue) {
            minValue = tempSum;
            employeeWithMinValue = col;
        }
    }
    JOptionPane.showMessageDialog(null, "Employee number " + employeeWithMinValue +
            " worked only " + minValue + " hours");

希望它有所帮助！

如何查找最小行总数并在2D数组中显示相应的名称

1 个答案: