Question

我有一个csv文件，其格式如下。

09:20:02.063,110.600,110.300,110.600
09:20:08.425,111.600,110.300,110.600
09:21:02.684,111.600,110.300,110.600
09:21:03.188,110.600,110.300,110.600
09:22:05.552,110.600,110.300,110.600
09:22:03.914,113.600,110.300,110.600
09:23:04.282,112.600,110.300,110.600
09:23:05.643,111.600,110.300,110.600
09:24:01.004,111.600,110.300,110.600
09:24:05.369,110.600,110.300,110.600

我想要删除以“09:23”开头的整行但是数据格式包括Hour：Minute：Second.Millisecond。我很难将Perl用于特定的“Hour：Minute”来删除行。任何建议，谢谢

预期结果

09:20:02.063,110.600,110.300,110.600
09:20:08.425,111.600,110.300,110.600
09:21:02.684,111.600,110.300,110.600
09:21:03.188,110.600,110.300,110.600
09:22:05.552,110.600,110.300,110.600
09:22:03.914,113.600,110.300,110.600
09:24:01.004,111.600,110.300,110.600
09:24:05.369,110.600,110.300,110.600

Answer 1

你可以试试这个，

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或

使用grep，

$ perl -lne 'print if !/^09:23\b/' file
09:20:02.063,110.600,110.300,110.600
09:20:08.425,111.600,110.300,110.600
09:21:02.684,111.600,110.300,110.600
09:21:03.188,110.600,110.300,110.600
09:22:05.552,110.600,110.300,110.600
09:22:03.914,113.600,110.300,110.600
09:24:01.004,111.600,110.300,110.600
09:24:05.369,110.600,110.300,110.600

Perl从特定字符串

1 个答案: