检测应用程序是否在iOS 9中的幻灯片放映或拆分视图模式下运行

时间：2015-07-12 11:40:47

标签： ios ipad multitasking ios9

在iOS 9中，是否可以检测应用程序何时在iOS 9的“幻灯片放映”或“拆分视图”模式下运行？

我已尝试通过Apple的documentation阅读iOS 9多任务处理，但对此没有任何好运......

我问，因为我的应用程序中可能有一个功能，我想在幻灯片结束时打开应用程序时禁用该功能。

15 个答案:

答案 0 :(得分：33)

只需检查您的窗口是否占据整个屏幕：

BOOL isRunningInFullScreen = CGRectEqualToRect([UIApplication sharedApplication].delegate.window.frame, [UIApplication sharedApplication].delegate.window.screen.bounds);

如果这是错误的，那么您将在拆分视图或幻灯片中运行。

以下是剪切的代码，它将自动维护此标志而不管旋转

-(void)traitCollectionDidChange:(UITraitCollection *)previousTraitCollection
{
 // simply create a property of 'BOOL' type
 isRunningInFullScreen = CGRectEqualToRect([UIApplication sharedApplication].delegate.window.frame, [UIApplication sharedApplication].delegate.window.screen.bounds);
}

答案 1 :(得分：15)

重新包装所有这些

的另一种方法 
extension UIApplication {
    public var isSplitOrSlideOver: Bool {
        guard let w = self.delegate?.window, let window = w else { return false }
        return !window.frame.equalTo(window.screen.bounds)
    }
}

然后你可以

    Swift中的
  • UIApplication.shared.isSplitOrSlideOver
    • Objective-C中的
  • UIApplication.sharedApplication.isSplitOrSlideOver

请注意，在Swift中，window对象是双重可选... WTF！

答案 2 :(得分：9)

我迟到了，但是如果你想要一个独立于方向工作的房产，试试这个：

extension UIApplication 
{
    func isRunningInFullScreen() -> Bool
    {
        if let w = self.keyWindow
        {
            let maxScreenSize = max(UIScreen.mainScreen().bounds.size.width, UIScreen.mainScreen().bounds.size.height)
            let minScreenSize = min(UIScreen.mainScreen().bounds.size.width, UIScreen.mainScreen().bounds.size.height)
            let maxAppSize = max(w.bounds.size.width, w.bounds.size.height)
            let minAppSize = min(w.bounds.size.width, w.bounds.size.height)
            return maxScreenSize == maxAppSize && minScreenSize == minAppSize
        }

        return true
    }
}

答案 3 :(得分：3)

您可以同时观看-willTransitionToTraitCollection：withTransitionCoordinator：用于size类，viewWillTransitionToSize：withTransitionCoordinator：用于视图的CGSize。但不建议使用硬编码的大小值。

答案 4 :(得分：3)

I recently had to determine display style of an application based including, not only if it changed to split view or slide-over, but also what portion of the screen was being utilized for the application (full, 1/3, 1/2, 2/3). Adding this to a ViewController subclass was able to solve the issue. 

/// Dismisses this ViewController with animation from a modal state.
func dismissFormSheet () {
    dismissViewControllerAnimated(true, completion: nil)
}

private func deviceOrientation () -> UIDeviceOrientation {
    return UIDevice.currentDevice().orientation
}

private func getScreenSize () -> (description:String, size:CGRect) {
    let size = UIScreen.mainScreen().bounds
    let str = "SCREEN SIZE:\nwidth: \(size.width)\nheight: \(size.height)"
    return (str, size)
}

private func getApplicationSize () -> (description:String, size:CGRect) {
    let size = UIApplication.sharedApplication().windows[0].bounds
    let str = "\n\nAPPLICATION SIZE:\nwidth: \(size.width)\nheight: \(size.height)"
    return (str, size)
}


func respondToSizeChange (layoutStyle:LayoutStyle) {
    // Respond accordingly to the change in size.
}

enum LayoutStyle: String {
    case iPadFullscreen         = "iPad Full Screen"
    case iPadHalfScreen         = "iPad 1/2 Screen"
    case iPadTwoThirdScreeen    = "iPad 2/3 Screen"
    case iPadOneThirdScreen     = "iPad 1/3 Screen"
    case iPhoneFullScreen       = "iPhone"
}

private func determineLayout () -> LayoutStyle {
    if UIDevice.currentDevice().userInterfaceIdiom == .Phone {
        return .iPhoneFullScreen
    }
    let screenSize = getScreenSize().size
    let appSize = getApplicationSize().size
    let screenWidth = screenSize.width
    let appWidth = appSize.width
    if screenSize == appSize {
        return .iPadFullscreen
    }

    // Set a range in case there is some mathematical inconsistency or other outside influence that results in the application width being less than exactly 1/3, 1/2 or 2/3.
    let lowRange = screenWidth - 15
    let highRange = screenWidth + 15

    if lowRange / 2 <= appWidth && appWidth <= highRange / 2 {
        return .iPadHalfScreen
    } else if appWidth <= highRange / 3 {
        return .iPadOneThirdScreen
    } else {
        return .iPadTwoThirdScreeen
    }

}

override func traitCollectionDidChange(previousTraitCollection: UITraitCollection?) {
    super.traitCollectionDidChange(previousTraitCollection)
    respondToSizeChange(determineLayout())
}

答案 5 :(得分：2)

滑动或33％分割视图时，水平尺寸类将是紧凑的。一旦你达到50％或66％，我认为你无法察觉。

答案 6 :(得分：1)

经过多次修补后，我找到了适用于我的应用程序的解决方案：

在AppDelegate.swift中，创建以下变量：

var slideOverActive: Bool = false

然后，在所有视图控制器中，将 UIApplicationDelegate 添加到类定义，创建 appDelegate 变量，然后添加以下 traitCollectionDidChange 功能：

class myViewController: UIViewController, UIApplicationDelegate {

var appDelegate = UIApplication.sharedApplication().delegate as! AppDelegate

override func traitCollectionDidChange(previousTraitCollection: UITraitCollection?) {

        let screenWidth = UIScreen.mainScreen().bounds.width

        if previousTraitCollection != nil {
            let horizontalSizeClass: Int = previousTraitCollection!.horizontalSizeClass.rawValue

            if screenWidth == 1024 || screenWidth == 768 { // iPad

                if horizontalSizeClass == 2 { // Slide Over is ACTIVE!

                    appDelegate.slideOverActive = true

                } else {

                    appDelegate.slideOverActive = false

                }
            }
        }
    }

}

然后，无论您在代码中想要检查滑动是否处于活动状态，只需检查：

if appDelegate.slideOverActive == true {

    // DO THIS

} else {

    // DO THIS

}

这是一种解决方法，但目前它对我有用。

快乐的小道！

答案 7 :(得分：1)

类似于Dan Rosenstark的解决方案，但更改为在新的iPad Pro上工作，该iPad Pro似乎报告了不同的帧和屏幕。根据它是否通过Xcode直接在设备上运行或是否已编译并发布，限制了高度通过TestFlight或App Store。通过AS或TF时，高度将返回980，而不是Xcode希望的高度，导致高度不可能返回true。

extension UIApplication {
    public var isSplitOrSlideOver: Bool {
        guard let w = self.delegate?.window, let window = w else { return false }
        return !(window.frame.width == window.screen.bounds.width)
    }
}

答案 8 :(得分：1)

这是我在iPhone / iPad iOS应用中使用的一种没有常数的更简单，更不易碎的方法。

此代码还可以区分幻灯片和拆分视图。

为清楚起见，我在这里返回String值，可以自由使用枚举值并合并两种全屏情况以适合您的应用。

-------------------------------------
| user_id| segment_array            |
-------------------------------------
| 100    | [seg1, seg3, seg4] |
| 200    | [seg3, seg4]             |
| 300    | [seg1, seg2, seg5]       |
-------------------------------------

答案 9 :(得分：0)

我参加派对的时间已经很晚了！但是，这是一个简单，快捷的解决方案。使用let width = UIScreen.mainScreen().applicationFrame.size.width，我们可以检测应用程序窗口的宽度，然后在小于某个数字时（即在iPhone屏幕上或在拆分视图中）发生事情，这对于在较小的屏幕上进行不同的事情很有用。为了让计算机一遍又一遍地检查宽度，我们可以每百分之一秒运行一次NSTimer，然后在宽度高于/低于某些东西的情况下进行操作。

为您量身定做的一些测量（您必须确定在上方/下方出现的宽度）： iPhone 6S Plus：414.0mm
iPhone 6S：375.0mm
iPhone 5S：320.0mm
iPad（肖像）：768.0mm
iPad（1/3分割视图）：320.0mm
iPad Air 2（1/2分割视图）：507.0mm
iPad（风景）：1024.0mm

以下是代码段：

class ViewController: UIViewController {

var widthtimer = NSTimer()

func checkwidth() {

var width = UIScreen.mainScreen().applicationFrame.size.width

if width < 507 { // The code inside this if statement will occur if the width is below 507.0mm (on portrait iPhones and in iPad 1/3 split view only). Use the measurements provided in the Stack Overflow answer above to determine at what width to have this occur.

    // do the thing that happens in split view
    textlabel.hidden = false

} else if width > 506 {

    // undo the thing that happens in split view when return to full-screen
    textlabel.hidden = true

}
}


override func viewDidAppear(animated: Bool) {

widthtimer = NSTimer.scheduledTimerWithTimeInterval(0.01, target: self, selector: "checkwidth", userInfo: nil, repeats: true) 
// runs every hundredth of a second to call the checkwidth function, to check the width of the window.

}

override func viewDidDisappear(animated: Bool) {
widthtimer.invalidate()
}

}

我希望这可以帮助任何偷看的人！

答案 10 :(得分：0)

添加@ Tamas的回答：
以下是无论轮换如何都会自动维护此标志的代码段。

 -(void)traitCollectionDidChange:(UITraitCollection *)previousTraitCollection
{
 // simply create a property of 'BOOL' type
 isRunningInFullScreen = CGRectEqualToRect([UIApplication sharedApplication].delegate.window.frame, [UIApplication sharedApplication].delegate.window.screen.bounds);
}

答案 11 :(得分：0)

我根据@Michael Voccola的图书馆写了一个SizeClasser图书馆 您可以使用视图控制器的traitCollection对其进行初始化，并检测拆分视图以及设备特定方向 因此，您可以专门编写代码1/3水平分割视图或1/3纵向分割视图UITraitCollection无法检测到它们。
https://github.com/cemolcay/SizeClasser

答案 12 :(得分：0)

尝试[UIScreen mainScreen] .bounds， self.window.screen.bounds， self.window.frame， UIApplication.sharedApplication.keyWindow.frame等，唯一可行的解​​决方案是弃用方法

CGRect frame = [UIScreen mainScreen].applicationFrame;

我以这种方式修复了

CGRect frame = [UIScreen mainScreen].applicationFrame;
frame = CGRectMake(0, 0, frame.size.width + frame.origin.x, frame.size.height + frame.origin.y);
self.window.frame = frame;

答案 13 :(得分：-1)

通过使用以下代码，您可以检查splitViewController是否折叠

if splitViewController?.isCollapsed ?? false {
    // splitview collapsed
} else {
    // splitview not collapsed
 }

答案 14 :(得分：-1)

我对@Michael Voccola解决方案进行了修改，解决了定向问题

我在这种情况下使用这种方法来检测所有iPad的分屏状态和处理布局 只需致电determineLayout()即可获取当前的layoutStyle 

private func getScreenSize() -> CGRect { 
     let size = UIScreen.main.bounds
     return size
}

private func getApplicationSize() -> CGRect {
    let size = UIApplication.shared.windows[0].bounds
    return size
}

enum LayoutStyle: String {
    case iPadFullscreen = "iPad Full Screen"
    case iPadHalfScreen = "iPad 1/2 Screen"
    case iPadTwoThirdScreeen = "iPad 2/3 Screen"
    case iPadOneThirdScreen = "iPad 1/3 Screen"
    case iPhoneFullScreen = "iPhone"
}

func determineLayout() -> LayoutStyle {

    if UIDevice.current.userInterfaceIdiom == .phone {
        return .iPhoneFullScreen
    }

    let screenSize = getScreenSize().size
    let appSize = getApplicationSize().size
    let screenWidth = screenSize.width
    let appWidth = appSize.width

    if screenSize == appSize {
//       full screen
         return .iPadFullscreen
    }

    let persent = CGFloat(appWidth / screenWidth) * 100.0

    if persent <= 55.0 && persent >= 45.0 {
//      The view persent between 45-55 that's mean it's half screen
        return .iPadHalfScreen
    } else if persent > 55.0 {
//      more than 55% that's mean it's 2/3
        return .iPadTwoThirdScreeen
    } else {
//      less than 45% it's 1/3
        return .iPadOneThirdScreen
    }
}
相关问题
最新问题