__asm { //
push eax //
push ecx //
movsx ecx, temp_char //
lea eax, EKey //
call encryptX // encrypt the character
mov temp_char, al //
pop ecx //
pop eax //
}
EChars[i] = temp_char; // Store encrypted char in the encrypted chars array
}
return;
// ---------------------------- start of ASM code ---------------------------------------------------------------encryptX: push ecx //push to manipulate
xchg eax, ecx //exchange values in eax and ecx / eax holds old ecx
neg al //twos complement least most eax byte (old ecx)
ror al, 1 //rotate right least most byte by 1 of eax
xor al, byte ptr[ecx] //exlcusive or least most byte against ecx value being pointed at
push edx //push edx onto stack for manipulatio
mov edx, eax //move eax into edx
xchg eax, ecx //swap values of ecx and eax
rol byte ptr[eax], 3 //rotate left the byte being pointed at 3 times
xor dl, byte ptr[eax] //xor the least byte by pointed value in eax
rol dl, 2 //rotate left the least byte in edx by 2
mov eax, edx //move edx value into eax
pop edx //pop values out
pop ecx //pop values out
ret //return
}
我的任务是在此代码中实现标准调用 - 即cdecl或std调用
' mov eax,[ebp + 8] //获取第一个被推送的参数'
我理解推动指针位置的想法,但我不确定我会告诉指针的位置。
是mov eax,[ebp + 4/8/12]还是你有什么
任何有助于告诉我如何做到这一点的帮助将不胜感激,同样如果你们其中一个善良的人解决了这个问题,可以添加一个解释
由于