Question

L = [98,75,92,87,89,90,92,87]

def mode(L):

    shows = []
    modeList = []

    L.sort()

    length = len(L)

    for num in L:
        count = L.count(num)
        shows.append(count)

    print 'List = ', L

    maxI = shows.index(max(shows))

    for i in shows:
        if i == maxI:
            if modeList == []:
                mode = L[i]
                modeList.append(mode)
                print 'Mode = ', mode
            elif mode not in modeList:
                mode = L[i]
                modeList.append(mode)
                print 'Mode = ', mode
            return mode


mode(L)

我似乎无法正确地遍历我的列表...... 我可以使用第二个for循环成功获得第一个返回＆gt;＆gt;＆gt;（模式= 87）的模式但是，我无法搜索列表的其余部分以便它也会返回＆gt ;＆gt;＆gt;（模式= 92）

我已经删除了我在Mode = 92的尝试，你能帮忙填补空白吗？

由于

Answer 1

与collections.Counter

相同的想法

from collections import Counter

L = [98,75,92,87,89,90,92,87]

def mode(L):
    # count the occurring frequencies
    count = Counter(L)

    # find the max
    mx = max(count.values())

    # collect the frequencies that occur the most
    modes = [f for f, m in count.items() if  m == mx]

    return modes

print(mode(L))
# [87, 92]

Answer 2

代码很好。我重写了一点。见下面的代码：

L = [98,75,92,87,89,90,92,87]

def mode(L):

    # Create a frequency table
    freq = {}
    for num in L:
        if not num in freq:
            freq[num] = 1
        else:
            freq[num] += 1

    # Gets maximal occurence
    maxoccurence = 0
    for f in freq:
        maxoccurence = max(maxoccurence, freq[f])

    # Put all the numbers with the occurence in  a list
    modes = []
    for f in freq:
        if freq[f] == maxoccurence:
            modes += [f]

    # Returns the list
    return modes

print(mode(L))

找到列表的模式

2 个答案: