我正在创建一个包含100个活动的应用。每个活动有10个问题，用户猜对了。这是很多编码。如何使编码变得简单 - 使用数组，重构或一些我不知道的设计模式？请参阅下面的代码。
每项活动都很相似，但有不同的问题和答案。
任何帮助都将不胜感激。
private TextView whoami3;
private TextView isa1,isa2,isa3,isa4,isa5,isa6,isa7,isa8,isa9,isa10;
private Button myclick;
private EditText answer;
private TextView mycorrect;
private TextView mytryagain;
private Button next_button;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_isaiah);
whoami3 = (TextView) findViewById(R.id.whoami3);
isa1 = (TextView) findViewById(R.id.isa1);
isa2 = (TextView) findViewById(R.id.isa2);
isa3 = (TextView) findViewById(R.id.isa3);
isa4 = (TextView) findViewById(R.id.isa4);
isa5 = (TextView) findViewById(R.id.isa5);
isa6 = (TextView) findViewById(R.id.isa6);
isa7 = (TextView) findViewById(R.id.isa7);
isa8 = (TextView) findViewById(R.id.isa8);
isa9 = (TextView) findViewById(R.id.isa9);
isa10 = (TextView) findViewById(R.id.isa10);
myclick = (Button) findViewById(R.id.myclick);
answer = (EditText) findViewById(R.id.answer);
mycorrect = (TextView) findViewById(R.id.mycorrect);
mytryagain = (TextView) findViewById(R.id.mytryagain);
next_button = (Button) findViewById(R.id.next_button);
whoami3.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
TextView whoami3 = (TextView) findViewById(R.id.whoami3);
TextView isa1 = (TextView) findViewById(R.id.isa1);
TextView isa2 = (TextView) findViewById(R.id.isa2);
TextView isa3 = (TextView) findViewById(R.id.isa3);
TextView isa4 = (TextView) findViewById(R.id.isa4);
TextView isa5 = (TextView) findViewById(R.id.isa5);
TextView isa6 = (TextView) findViewById(R.id.isa6);
TextView isa7 = (TextView) findViewById(R.id.isa7);
TextView isa8 = (TextView) findViewById(R.id.isa8);
TextView isa9 = (TextView) findViewById(R.id.isa9);
TextView isa10 = (TextView) findViewById(R.id.isa10);
Button ansewer = (Button) findViewById(R.id.myclick);
TextView mycorrect = (TextView) findViewById(R.id.mycorrect);
TextView mytryagain = (TextView) findViewById(R.id.mytryagain);
if (whoami3.isShown()) {
whoami3.setVisibility(View.INVISIBLE);
isa1.setVisibility(View.VISIBLE);
} else {
whoami3.setVisibility(View.VISIBLE);
}
}
});
isa1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa1.isShown()) {
isa1.setVisibility(View.INVISIBLE);
isa2.setVisibility(View.VISIBLE);
} else {
isa1.setVisibility(View.VISIBLE);
}
}
});
isa2.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa2.isShown()) {
isa2.setVisibility(View.INVISIBLE);
isa3.setVisibility(View.VISIBLE);
} else {
isa2.setVisibility(View.VISIBLE);
}
}
});
isa3.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa3.isShown()) {
isa3.setVisibility(View.INVISIBLE);
isa4.setVisibility(View.VISIBLE);
} else {
isa3.setVisibility(View.VISIBLE);
}
}
});
isa4.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa4.isShown()) {
isa4.setVisibility(View.INVISIBLE);
isa5.setVisibility(View.VISIBLE);
} else {
isa4.setVisibility(View.VISIBLE);
}
}
});
isa5.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa5.isShown()) {
isa5.setVisibility(View.INVISIBLE);
isa6.setVisibility(View.VISIBLE);
} else {
isa5.setVisibility(View.VISIBLE);
}
}
});
isa6.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa6.isShown()) {
isa6.setVisibility(View.INVISIBLE);
isa7.setVisibility(View.VISIBLE);
} else {
isa6.setVisibility(View.VISIBLE);
}
}
});
isa7.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa7.isShown()) {
isa7.setVisibility(View.INVISIBLE);
isa8.setVisibility(View.VISIBLE);
} else {
isa7.setVisibility(View.VISIBLE);
}
}
});
isa8.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa8.isShown()) {
isa8.setVisibility(View.INVISIBLE);
isa9.setVisibility(View.VISIBLE);
} else {
isa8.setVisibility(View.VISIBLE);
}
}
});
isa9.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (isa9.isShown()) {
isa9.setVisibility(View.INVISIBLE);
isa10.setVisibility(View.VISIBLE);
} else {
isa9.setVisibility(View.VISIBLE);
}
}
});
myclick.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String yourString = "ISAIAH";
if (answer.getText().toString().trim().toLowerCase().equals("ISAIAH".toString().trim().toLowerCase())) {
mycorrect.setVisibility(View.VISIBLE);
} else {
mytryagain.setVisibility(View.VISIBLE);
if (answer.getText().toString().trim().toLowerCase()!=("MARK".toString().trim().toLowerCase())) {
answer.setText("");
}
}
mytryagain.setText("Sorry, Try again");
mytryagain.postDelayed(new Runnable() {
@Override
public void run() {
mytryagain.setVisibility(View.INVISIBLE);
}
}, 2000);
}
});
}
public void onClick(View view){
Random rnd = new Random();
int x=rnd.nextInt(4)+1;
Intent intent = new Intent();
switch (x){
case 1:
intent.setClass(this,John.class);
break;
case 2:
intent.setClass(this,Caleb.class);
break;
case 3:
intent.setClass(this,Mark.class);
break;
case 4:
intent.setClass(this,Jacob.class);
break;
}
startActivity(intent);
finish();
}
答案 0 :(得分：0)
您可以使用Class.forName（）方法，因此onClick方法可以像这样重写：
Random rnd = new Random();
int x=rnd.nextInt(4);
String[] clazzes = {John.class.getName(), Caleb.class.getName(), Mark.class.getName(), Jacob.class.getName()};
Intent intent = new Intent();
try {
intent.setClass(this, Class.forName(clazzes[x]));
startActivity(intent);
finish();
} catch (Exception e) {
// your exception here when class not found here
}
但如果你有相同的UI，100个活动的功能，我建议你只使用1个活动，但通过Intent发送差异数据。