lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}
# Add your function below!
def average(numbers):
total=sum(numbers)
avg=float(total)/len(numbers)
return avg
students=[lloyd,alice,tyler]
def get_average(student):
for a in student:
homework=average(a["homework"])
quizzes=average(a["quizzes"])
tests=average(a["tests"])
student= .1 * homework + .3 * quizzes + .6 * tests
return student
print get_average(students)
上面的代码只输出一个学生Tyler的平均值,这是此列表students=[lloyd,alice,tyler]
中的最后一个。
但是我认为这个列表不起作用,但Codecademy确实在他们的课程中使用了这个列表。 我希望打印所有三个学生的平均值。请帮助..提前谢谢。
答案 0 :(得分:0)
您只使用student
的最后一个值,如果您希望全部查看,则需要在每次迭代中附加所有学生值:
def get_average(students):
students_avs = []
for a in students:
homework = average(a["homework"])
quizzes = average(a["quizzes"])
tests = average(a["tests"])
student= .1 * homework + .3 * quizzes + .6 * tests
students_avs.append(student) # append each result
return students_avs
输出:
In [13]: get_average(students)
Out[13]: [80.55, 91.14999999999999, 79.9]
student= .1 * homework + .3 * quizzes + .6 * tests
指向每次迭代的新值,因此从逻辑上讲,您只能看到为最终学生计算的最后一个值,因为您从未在自己的代码中保存每次迭代的值。
您还可以返回列表理解:
def get_average(students):
return [.1 * average(a["homework"]) + .3 * average(a["quizzes"]) + .6 * average(a["tests"])
for a in students]
另一种选择是对单个学生使用get_average
并在列表comp中调用该函数:
def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
student = .1 * homework + .3 * quizzes + .6 * tests
return student
out = [get_average(d) for d in students]
print(out)