Question

我有我的数据

windspeed      month
1.2             Jan
2               Feb
3.5             Mar
2.6             Apr
5.9             Jun
2.5             Jul

我想获得这种数据

Jan   Feb   Mar   Apr    Jun   Jul  
1.2    2     3.5    2.6   5.9   2.5

Answer 1

只是基数R（即使setNames实际上属于stats包）：

setNames(dat$windspeed, dat$month)
Jan Feb Mar Apr Jun Jul 
1.2 2.0 3.5 2.6 5.9 2.5

是的，有一种方式，这里是一种方式：

as.data.frame(t(setNames(dat$windspeed, dat$month)))
  Jan Feb Mar Apr Jun Jul
1 1.2   2 3.5 2.6 5.9 2.5

Answer 2

怎么样？

t(unstack(DF, windspeed ~ month))

    Apr Feb Jan Jul Jun Mar
res 2.6   2 1.2 2.5 5.9 3.5

Answer 3

R中也有一些非常有用的包，适用于reshape，data.table，tidyr

等操作

library(reshape2)
library(data.table)

dcast.data.table(melt(setDT(data), id.vars = "month"), variable ~ month)
#   variable Apr Feb Jan Jul Jun Mar
#1: windspeed 2.6   2 1.2 2.5 5.9 3.5

library(reshape2)
library(tidyr)
spread(melt(data), month, value)

#   variable Apr Feb Jan Jul Jun Mar
#1 windspeed 2.6   2 1.2 2.5 5.9 3.5

Answer 4

你可以试试这个：

DF <- data.frame(windspeed=c(1.2, 2, 3.5, 2.6, 5.9, 2.5), month=c('Jan', 'Feb', 'Mar', 'Apr', 'Jun', 'Jul'))
DF <- t(DF)
colnames(DF) = DF[2, ]
DF <- DF[1,]
DF

给你

 Jan   Feb   Mar   Apr   Jun   Jul 
"1.2" "2.0" "3.5" "2.6" "5.9" "2.5"

如何用r传播数据

4 个答案: