以下型号:
class User extends Doctrine_Record {
public function setTableDefinition() {
$this->hasColumn ( 'iron', 'integer', 4 );
}
public function setUp() {
$this->hasMany ('Field as Fields', array(
'local' => 'id',
'foreign' => 'owner_id'
));
}
}
class Field extends Doctrine_Record {
public function setTableDefinition() {
$this->hasColumn('owner_id','integer',4);
$this->hasColumn('ressource_id','integer',4);
$this->hasColumn('ressource_amount','integer','2');
}
public function setUp() {
$this->hasOne('User as Owner',array(
'local' => 'owner_id',
'foreign' => 'id'
));
}
}
我尝试遵循DQL:
$sqlRessourceUpdate = Doctrine_Query::create()
->update('Field f')
->set('f.Owner.iron','f.Owner.iron + f.ressource_amount')
->where('f.ressource_id = ?',1);
结果:
'Doctrine_Query_Exception' with message 'Unknown component alias f.Owner'
基本上我只是想根据字段的值更新字段所有者的“铁”属性
答案 0 :(得分:1)
我猜您无法在查询中引用其他类似的表。
这可能不是最好的方法,但是,这就是我的工作
$q = Doctrine_Query::create()
->select('*')
->from('Field')
->where('ressource_id = ?',1); //btw resource has one 's'
$field = $q->fetchone();
$field->Owner['Iron'] += $field->ressource_amount;
$field->save();
编辑: 实际上我不知道这是否有用......这更像我的工作
$q = Doctrine_Query::create()
->select('*')
->from('Field')
->where('ressource_id = ?',1); //btw resource has one 's'
$field = $q->fetchone();
$user = $field->Owner;
$user['Iron'] += $field->ressource_amount; // I have never used a += like this, but in theory it will work.
$user->save();