Question

我有一个shell脚本，可以创建一个文本文件，其中包含我相机的当前设置：

#!/bin/sh
file="test.txt"
[[ -f "$file" ]] && rm -f "$file"

var=$(gphoto2 --summary)
echo "$var" >> "test.txt" 


if [ $? -eq 0 ]
then
    echo "Successfully created file"
    exit 0
else
    echo "Could not create file" >&2
    exit 1
fi

当我从终端运行脚本时，脚本正常工作，但是当我运行以下处理应用程序时，文本文件已创建，但不包含来自摄像头的任何信息：

import java.util.*;
import java.io.*;

void setup() {
    size(480, 120);
    camSummary();
}

void draw() {
}
void camSummary() {
    String commandToRun = "./ex2.sh"; 
    File workingDir = new File("/Users/loren/Documents/RC/CamSoft/");
    String returnedValues;    // value to return any results 


    try {
        println("in try");
        Process p = Runtime.getRuntime().exec(commandToRun, null, workingDir);
        int i = p.waitFor();
        if (i==0) {
            BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream()));
            while ( (returnedValues = stdInput.readLine ()) != null) {
            println(returnedValues);
            }
       } else{
            println("i is:  " + i); 
       }
   }
   catch(Throwable t) {
       println(t);
   }
}

最后，我想直接从脚本中读取一些数据到变量中，然后在处理中使用这些变量。

有人可以帮我解决这个问题吗？

谢谢，

洛伦

替代脚本：

#!/bin/sh

set -x
exec 2>&1

file="test.txt"
[ -f "$file" ] && rm -f "$file"


# you want to store the output of gphoto2 in a variable
# var=$(gphoto2 --summary)
# problem 1: what if PATH environment variable is wrong (i.e. gphoto2 not accessible)?
# problem 2: what if gphoto2 outputs to stderr?
# it's better first to:

echo first if
if ! type gphoto2 > /dev/null 2>&1; then
    echo "gphoto2 not found!" >&2
    exit 1
fi

echo second if
# Why using var?...
gphoto2 --summary > "$file" 2>&1
# if you insert any echo here, you will alter $?
if [ $? -eq 0 ]; then
    echo "Successfully created file"
    exit 0
else
    echo "Could not create file" >&2
    exit 1
fi

Answer 1

您的shell脚本中存在几个问题。让我们一起纠正并改进它。

#!/bin/sh

file="test.txt"
[ -f "$file" ] && rm -f "$file"

# you want to store the output of gphoto2 in a variable
# var=$(gphoto2 --summary)
# problem 1: what if PATH environment variable is wrong (i.e. gphoto2 not accessible)?
# problem 2: what if gphoto2 outputs to stderr?
# it's better first to:
if ! type gphoto2 > /dev/null 2>&1; then
    echo "gphoto2 not found!" >&2
    exit 1
fi
# Why using var?...
gphoto2 --summary > "$file" 2>&1
# if you insert any echo here, you will alter $?
if [ $? -eq 0 ]; then
    echo "Successfully created file"
    exit 0
else
    echo "Could not create file" >&2
    exit 1
fi

从处理中运行的脚本未正确执行

1 个答案: