from datetime import datetime
import time
for i in range(1000):
curr_time = datetime.now()
print(curr_time)
time.sleep(0.0001)
我正在测试datetime.now()
的分辨率。由于它假设以微秒为单位输出,我预计每次打印都会有所不同。
然而,我总是得到类似的东西。
...
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.212073
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
2015-07-10 22:38:47.213074
...
为什么会这样?有什么方法可以让我得到一个精确的时间戳到微秒?实际上我不需要微秒,但获得0.1ms的分辨率会很不错。
===更新====
我将它与使用time.perf_counter()进行比较并添加到起始datetime
从datetime import datetime,timedelta
进口时间
datetime0 = datetime.now()
t0 = time.perf_counter()
for i in range(1000):
print('datetime.now(): ', datetime.now())
print('time.perf_counter(): ', datetime0 + timedelta(0, time.perf_counter()-t0))
print('\n')
time.sleep(0.000001)
我不确定它到底有多“准确”,但分辨率至少要高......这似乎并不重要,因为我的电脑甚至无法以高速打印。为了我的目的,我只需要不同的时间戳来区分不同的条目,这对我来说已经足够了。
...
datetime.now(): 2015-07-10 23:24:18.010377
time.perf_counter(): 2015-07-10 23:24:18.010352
datetime.now(): 2015-07-10 23:24:18.010377
time.perf_counter(): 2015-07-10 23:24:18.010545
datetime.now(): 2015-07-10 23:24:18.010377
time.perf_counter(): 2015-07-10 23:24:18.010745
datetime.now(): 2015-07-10 23:24:18.011377
time.perf_counter(): 2015-07-10 23:24:18.010961
datetime.now(): 2015-07-10 23:24:18.011377
time.perf_counter(): 2015-07-10 23:24:18.011155
datetime.now(): 2015-07-10 23:24:18.011377
time.perf_counter(): 2015-07-10 23:24:18.011369
datetime.now(): 2015-07-10 23:24:18.011377
time.perf_counter(): 2015-07-10 23:24:18.011596
datetime.now(): 2015-07-10 23:24:18.012379
time.perf_counter(): 2015-07-10 23:24:18.011829
datetime.now(): 2015-07-10 23:24:18.012379
time.perf_counter(): 2015-07-10 23:24:18.012026
datetime.now(): 2015-07-10 23:24:18.012379
time.perf_counter(): 2015-07-10 23:24:18.012232
datetime.now(): 2015-07-10 23:24:18.012379
time.perf_counter(): 2015-07-10 23:24:18.012424
datetime.now(): 2015-07-10 23:24:18.012379
time.perf_counter(): 2015-07-10 23:24:18.012619
datetime.now(): 2015-07-10 23:24:18.013380
time.perf_counter(): 2015-07-10 23:24:18.012844
datetime.now(): 2015-07-10 23:24:18.013380
time.perf_counter(): 2015-07-10 23:24:18.013044
datetime.now(): 2015-07-10 23:24:18.013380
time.perf_counter(): 2015-07-10 23:24:18.013242
datetime.now(): 2015-07-10 23:24:18.013380
time.perf_counter(): 2015-07-10 23:24:18.013437
datetime.now(): 2015-07-10 23:24:18.013380
time.perf_counter(): 2015-07-10 23:24:18.013638
datetime.now(): 2015-07-10 23:24:18.014379
time.perf_counter(): 2015-07-10 23:24:18.013903
datetime.now(): 2015-07-10 23:24:18.014379
time.perf_counter(): 2015-07-10 23:24:18.014125
datetime.now(): 2015-07-10 23:24:18.014379
time.perf_counter(): 2015-07-10 23:24:18.014328
datetime.now(): 2015-07-10 23:24:18.014379
time.perf_counter(): 2015-07-10 23:24:18.014526
datetime.now(): 2015-07-10 23:24:18.014379
time.perf_counter(): 2015-07-10 23:24:18.014721
datetime.now(): 2015-07-10 23:24:18.015381
time.perf_counter(): 2015-07-10 23:24:18.014919
...
答案 0 :(得分:1)
这可能是您系统1 /path/here path/here/again
2 a/different/path/here another/path/here
的限制,而不是time.sleep
...或可能两者都有。 您运行的是什么操作系统以及Python的哪个版本和发行版?
您的系统可能无法提供datetime.now()
文档中提到的“亚秒级精度”:
time.sleep
在使用CPython 2.7的 Linux 3.x on amd64 上,我得到了一些非常接近你想要的0.0001时间步骤的东西:
sleep(...)
sleep(seconds)
Delay execution for a given number of seconds. The argument may be
a floating point number for subsecond precision.