Question

按下按钮时，我一直在尝试从数据源更新网格。

所以我在点击事件中有这样的事情：

$('#grid').jqGrid('trigger','reloadGrid');

然而，这不起作用，我得到一个未知方法'触发'的错误

我也试过

$('#grid').jqGrid('trigger("reloadGrid")');

我该如何执行此功能？

Answer 1

$('#grid').trigger( 'reloadGrid' );

Answer 2

这对我有用。

jQuery('#grid').jqGrid('clearGridData');
jQuery('#grid').jqGrid('setGridParam', {data: dataToLoad});
jQuery('#grid').trigger('reloadGrid');

Answer 3

尝试使用新数据重新加载jqGrid

def tile_repeat(n, repTime):
    '''
    create something like 111..122..2333..33 ..... n..nn 
    one particular number appears repTime consecutively.
    This is for flattening the indices.
    '''
    print n, repTime
    idx = tf.range(n)
    idx = tf.reshape(idx, [-1, 1])    # Convert to a n x 1 matrix.
    idx = tf.tile(idx, [1, repTime])  # Create multiple columns, each column has one number repeats repTime 
    y = tf.reshape(idx, [-1])
    return y

def gather_along_second_axis(x, idx):
    ''' 
    x has shape: [batch_size, sentence_length, word_dim]
    idx has shape: [batch_size, num_indices]
    Basically, in each batch, get words from sentence having index specified in idx
    However, since tensorflow does not fully support indexing,
    gather only work for the first axis. We have to reshape the input data, gather then reshape again
    '''
    reshapedIdx = tf.reshape(idx, [-1]) # [batch_size*num_indices]
    idx_flattened = tile_repeat(tf.shape(x)[0], tf.shape(x)[1]) * tf.shape(x)[1] + reshapedIdx
    y = tf.gather(tf.reshape(x, [-1,tf.shape(x)[2]]),  # flatten input
                idx_flattened)
    y = tf.reshape(y, tf.shape(x))
    return y

x = tf.constant([
            [[1,2,3],[3,5,6]],
            [[7,8,9],[10,11,12]],
            [[13,14,15],[16,17,18]]
    ])
idx=tf.constant([[0,1],[1,0],[1,1]])

y = gather_along_second_axis(x, idx)
with tf.Session(''):
    print y.eval()
    print tf.Tensor.get_shape(y)

Answer 4

var newdata= //You call Ajax peticion//

$("#idGrid").clearGridData();

$("#idGrid").jqGrid('setGridParam', {data:newdata)});
$("#idGrid").trigger("reloadGrid");

事件更新数据表中

如何刷新jqGrid中的数据？

4 个答案: