我构建了一个跟踪系统,其中包含来自其他表格的唯一workID
和Id
。我有一个名为乘数的列,如果满足某些条件,我想改变。我想更改每个记录的乘数列,其中:日期是星期日,星期六之前(表示星期六的日期需要在表中)并且具有与星期六相同的ID。
基本上这是一个奖励系统,如果一个跑步者在周六和周日工作,那么在那个周日他得到2的乘数。我打开每个星期日和星期六在表中的记录集并尝试匹配它们。但它跳过一些东西,因为星期六并不总是跟着星期天。
sqlFindSat = "Select WorkID, Date, Task, ID, Multiplier from tblA where (weekday([date]) = 7) order by date, id, workId"
sqlFindSun = "select WorkID, Date, Task, ID, Multiplier from tblA where ( weekday([date]) = 1 ) order by date, id, workId"
Set fwSun = db.OpenRecordset(sqlFindSun)
Set fwSat = db.OpenRecordset(sqlFindSat)
Do While Not fwSat.EOF
waitforsat = False
debug.print " Curr Sat: " & fwSat!Date & " Curr Sun: " & fwSun!Date
If WeekdayName(Weekday(fwSat!Date)) = "saturday" Then
If ((DateAdd("d", 1, fwSat!Date) = fwSun!Date) And (fwSun!ID = fwSat!ID)) Then
fwSun.Edit
fwSun!multiplier = 2
fwSun.Update
End If
End If
If Not fwSun.EOF Then
fwSun.MoveNext
End If
fwSat.MoveNext
Loop
只要星期六之后是星期日,我的代码就可以了。一个星期六没有一个星期天,然后游标处于不同的水平,有时一个。我不介意在SQL Update或其他任何内容中执行此操作,只要它在访问中有效。
注意:下面的示例不是真实样本。评论部分用于显示一周中的哪一天。
Workid | Date | ID | Multiplier | comments
12 10-11-2012 2 1 sunday
13 15-12-2012 4 1 Monday
14 10-10-2012 3 1 Saturday
25 11-10-2012 3 1 Sunday
17 8-10-2012 2 1 sunday
35 15-10-2012 4 1 Monday
45 8-10-2012 3 1 Saturday
50 9-10-2012 3 1 Sunday
Workid | Date | ID | Multiplier | comments
12 10-11-2012 2 1 Sunday
13 15-12-2012 4 1 Monday
14 10-10-2012 3 1 Saturday
25 11-10-2012 3 2 Sunday
17 8-10-2012 2 1 sunday
35 15-10-2012 4 1 Monday
45 8-10-2012 3 1 Saturday
50 9-10-2012 3 2 Sunday
从表中可以看出,之前的星期日。
答案 0 :(得分:1)
VBA不需要这样做;您也可以使用自联接运行SQL查询并直接执行更新。
对于具有相同ID的前一个星期六的记录的所有星期日行,此查询会将乘数更改为2。
语法应为:
UPDATE tblA t1
INNER JOIN tblA t2 ON t1.ID = t2.ID AND t2.Date = DATEADD('d', -1, t1.date)
SET t1.Multiplier = 2
WHERE WEEKDAY(t1.date) = 1 -- assuming 1 is Sunday, might depend on regional setting
如果您想查看在执行更新之前会发生什么,只需将更新更改为select *并删除set语句。
或者在运行之前对表进行备份:)
答案 1 :(得分:0)
根据您要访问的记录数量,我认为这应该对您有用:
第一个功能就是遍历fwsat
RecordSet
中的所有星期日。对于每个星期日,它将调用PrecedingSaturday
函数并检查该ID是否具有在该星期日的一天内的星期六。
Public Function CheckSunday()
sqlFindSat = "Select WorkID, Date, Task, ID, Multiplier from tblA where (weekday([date]) = 7) order by date, id, workId"
sqlFindSun = "select WorkID, Date, Task, ID, Multiplier from tblA where ( weekday([date]) = 1 ) order by date, id, workId"
Set fwSun = db.OpenRecordset(sqlFindSun)
Set fwsat = db.OpenRecordset(sqlFindSat)
'For all Sundays
Do While Not fwSun.EOF
'If this Sunday has a Preceding Saturday.
If PrecedingSaturday(fwsat, fwSun!id, fwSun!Date) Then
'Update multiplier to 2 for this Sunday
fwSun.Edit
fwSun!multiplier = 2
fwSun.Update
End If
fwSun.MoveNext
Loop
End Function
这个函数只是接受包含所有星期六的RecordSet
,并搜索它们以查看它们中是否有任何星期六在有问题的星期日之前。如果是,则返回true。
Public Function PrecedingSaturday(fwsat As Recordset, intID As Integer, dte As Date) As Boolean
Dim blnPrecedingSaturday As Boolean
blnPrecedingSaturday = False
'For all Saturdays while a preceding Saturday hasn't already been found
Do While Not fwsat.EOF And blnPrecedingSaturday = False
'If Saturday's ID and Sunday's id match
If fwsat!id = intID Then
'If the Saturday and Sunday happened within 1 day
If DateDiff("d", fwsat!Date, dte) = 1 Then
'This is a preceding Saturday
blnPrecedingSaturday = True
End If
End If
fwsat.MoveNext
Loop
PrecedingSaturday= blnPrecedingSaturday
End Function
这是粗略的代码,因为我没有表结构来正确测试它。虽然我认为它应该适用于您正在寻找的东西。