我正在尝试编写一个SQL调用，它将在任何所需的时间间隔内对权重平均数据进行计时。这意味着我只需要在查询中更改一些参数，这样最终输出将在我的两个所需日期之间的日，小时和/或分钟。
我还需要它来填充缺失间隔之间的数据，如本例
实际数据库数据
Time_Stamp Time_Stamp_ms BPS_FIT0161
2014-07-26 22:32:36 74 164
2014-07-26 22:32:37 71 164
2014-07-26 22:32:38 71 164
2014-07-26 22:32:39 70 162
2014-07-26 22:32:40 71 162
2014-07-26 22:32:41 67 162
2014-07-26 22:32:42 64 165
2014-07-26 22:32:43 63 164
2014-07-26 22:32:44 62 164
2014-07-26 22:32:45 63 163
2014-07-26 22:32:46 59 163
2014-07-26 22:32:47 56 165
2014-07-26 22:32:48 55 167
2014-07-26 22:32:49 54 167
2014-07-26 22:32:50 54 168
2014-07-26 22:32:51 51 168
2014-07-26 22:32:52 47 171
2014-07-26 22:32:53 46 173
2014-07-26 22:32:54 111 177
2014-07-26 22:32:55 42 178
2014-07-26 22:38:56 99 178
2014-07-26 23:24:57 426 178
2014-07-27 00:21:58 854 178
2014-07-27 01:53:09 229 178
2014-07-27 03:30:11 419 178
2014-07-27 05:25:14 56 178
2014-07-27 07:32:16 881 178
2014-07-27 09:48:20 48 178
2014-07-27 12:55:24 286 178
2014-07-27 16:13:28 562 178
2014-07-27 20:10:33 803 178
2014-07-28 00:56:40 26 178
2014-07-28 06:38:47 753 178
2014-07-28 08:38:47 753 178
2014-07-28 09:24:37 219 248
2014-07-28 09:24:38 218 248
2014-07-28 09:24:39 214 226
2014-07-28 09:24:40 212 226
2014-07-28 09:24:41 212 226
2014-07-28 09:24:42 208 224
2014-07-28 09:24:43 207 222
2014-07-28 09:24:44 206 222
2014-07-28 09:24:45 206 222
2014-07-28 10:11:45 604 202
SQL时间加权平均值（TWA）每小时查询应如下所示：
Date_time BPS_FIT0161 TWA
2014-07-26 22:00:00 177.4342105
2014-07-26 23:00:00 178
2014-07-27 00:00:00 178
2014-07-27 01:00:00 178
2014-07-27 02:00:00 178
2014-07-27 03:00:00 178
2014-07-27 04:00:00 178
2014-07-27 05:00:00 178
2014-07-27 06:00:00 178
2014-07-27 07:00:00 178
2014-07-27 08:00:00 178
2014-07-27 09:00:00 178
2014-07-27 10:00:00 178
2014-07-27 11:00:00 178
2014-07-27 12:00:00 178
2014-07-27 13:00:00 178
2014-07-27 14:00:00 178
2014-07-27 15:00:00 178
2014-07-27 16:00:00 178
2014-07-27 17:00:00 178
2014-07-27 18:00:00 178
2014-07-27 19:00:00 178
2014-07-27 20:00:00 178
2014-07-27 21:00:00 178
2014-07-27 22:00:00 178
2014-07-27 23:00:00 178
2014-07-28 00:00:00 178
2014-07-28 01:00:00 178
2014-07-28 02:00:00 178
2014-07-28 03:00:00 178
2014-07-28 04:00:00 178
2014-07-28 05:00:00 178
2014-07-28 06:00:00 178
2014-07-28 07:00:00 178
2014-07-28 08:00:00 178
2014-07-28 09:00:00 179.5349202
2014-07-28 10:00:00 202.0857852
非常感谢你的帮助！
http://sqlfiddle.com/#!6/a8db7/1
解决方案的开始
使用VKP的解决方案
SELECT dateadd(hour, datediff(hour, 0, Time_Stamp),0) as Date_Time,
sum(time_stamp_ms * bps_fit0161)/sum(time_stamp_ms) as weighted_avg
FROM BPS
WHERE Time_Stamp BETWEEN CONVERT(DATETIME, '2014-07-26 00:00:00', 102)
AND CONVERT(DATETIME, '2014-07-30 00:00:00', 102)
group by dateadd(hour, datediff(hour, 0, Time_Stamp),0),
dateadd(day,datediff(day, 0, Time_Stamp),0)
order by dateadd(hour, datediff(hour, 0, Time_Stamp),0),
dateadd(day,datediff(day, 0, Time_Stamp),0)
我的查询结果
Date_Time weighted_avg
2014-07-26 00:00:00.000 180
2014-07-26 01:00:00.000 113
2014-07-26 02:00:00.000 147
2014-07-26 03:00:00.000 221
2014-07-26 04:00:00.000 252
2014-07-26 05:00:00.000 379
2014-07-26 06:00:00.000 370
2014-07-26 07:00:00.000 253
2014-07-26 08:00:00.000 125
2014-07-26 09:00:00.000 119
2014-07-26 10:00:00.000 125
2014-07-26 11:00:00.000 117
2014-07-26 12:00:00.000 160
2014-07-26 13:00:00.000 123
2014-07-26 14:00:00.000 86
2014-07-26 15:00:00.000 81
2014-07-26 16:00:00.000 100
2014-07-26 17:00:00.000 108
2014-07-26 18:00:00.000 175
2014-07-26 19:00:00.000 238
2014-07-26 20:00:00.000 211
2014-07-26 21:00:00.000 231
2014-07-26 22:00:00.000 173
2014-07-26 23:00:00.000 178
2014-07-27 00:00:00.000 178
2014-07-27 01:00:00.000 178 <----- Start of missing Data!
2014-07-27 03:00:00.000 178
2014-07-27 05:00:00.000 178
2014-07-27 07:00:00.000 178
2014-07-27 09:00:00.000 178
2014-07-27 12:00:00.000 178
2014-07-27 16:00:00.000 178
2014-07-27 20:00:00.000 178
2014-07-28 00:00:00.000 178
2014-07-28 06:00:00.000 178
2014-07-28 09:00:00.000 160
2014-07-28 10:00:00.000 134
2014-07-28 11:00:00.000 113
2014-07-28 12:00:00.000 136
2014-07-28 13:00:00.000 131
2014-07-28 14:00:00.000 84
2014-07-28 15:00:00.000 102
正如您所看到的，由于我们的数据库处于脱机状态或网络上的无线节点失去通信，我错过了几个小时。您将在上述查询中更改为使用前一小时数据自动填充缺失的小时数，对于缺少数据的数据也是如此。
答案 0 :(得分：1)
declare @s datetime
declare @e datetime
set @s = '2014-07-26 00:00:00'
set @e = '2014-07-30 00:00:00'
;with x(n) as
(
SELECT TOP (DATEDIFF(HOUR, @s, @e) + 1)
rn = ROW_NUMBER() OVER (ORDER BY [object_id])
FROM sys.all_columns ORDER BY [object_id]
)
select DATEADD(HOUR, n-1, @s) as dt into t from x
;with y as (
SELECT
row_number() over(order by t.dt) as rn,
t.dt,
sum(time_stamp_ms * bps_fit0161) / sum(time_stamp_ms) as weighted_avg
FROM BPS
right join t on t.dt = dateadd(hour, datediff(hour, 0, Time_Stamp),0)
group by t.dt,dateadd(hour, datediff(hour, 0, Time_Stamp),0)
)
select y.dt ,
case when y.weighted_avg is null then prev_y.weighted_avg
else y.weighted_avg end as weighted_avg
from y
left join y prev_y on y.rn = prev_y.rn-1
试试这个。这个小组从任何一小时开始直到那个小时结束。
已编辑：包含指定时间之间的所有小时数。这可能会让您更接近您所寻找的目标。