Question

以下SQL Server 2008查询将名称列解析为单独的第一个，中间名和姓氏部分，并且工作得很好：

SELECT 
  LEFT(Name, CHARINDEX(' ', Name)) AS FirstName, 
  CASE WHEN CHARINDEX(' ', Name) <> LEN(Name) - CHARINDEX(' ', REVERSE(Name)) + 1 THEN 
        SUBSTRING(Name, CHARINDEX(' ', Name)+ 1, LEN(Name) - CHARINDEX(' ', REVERSE(Name))-CHARINDEX(' ', Name)) end as MiddleName, 
  RIGHT( Name, CHARINDEX(' ', REVERSE(Name))) AS LastName 
FROM a01_parse_test

我现在需要将分隔的部分（FirstName，MiddleName和LastName）存储到我的表格中（a01_parse_test）。我怎么能这样做？

Answer 1

好像您想要更新仅Name FirstName，MiddleName，LastName或TRIGGER的不同更改的原始源表格。如果是这样，我会考虑在源表上创建一个视图，以标准化您的逻辑以拆分名称，然后在视图上使用INSTEAD OF UPDATE添加IF OBJECT_ID('a01_parse_test') IS NULL BEGIN CREATE TABLE a01_parse_test (Id INT PRIMARY KEY NOT NULL IDENTITY(1,1), Name VARCHAR(500)) INSERT a01_parse_test VALUES ('Barack Hussein Obama'), ('George Walker Bush'), ('William Jefferson Clinton'), ('Ronald Wilson Reagan') END IF OBJECT_ID('v_ParseNames') IS NOT NULL DROP VIEW v_ParseNames GO CREATE VIEW v_ParseNames AS SELECT Id, -- Whatever the id is of your parsing table LEFT(Name, CHARINDEX(' ', Name)) AS FirstName, CASE WHEN CHARINDEX(' ', Name) <> LEN(Name) - CHARINDEX(' ', REVERSE(Name)) + 1 THEN SUBSTRING(Name, CHARINDEX(' ', Name)+ 1, LEN(Name) - CHARINDEX(' ', REVERSE(Name))-CHARINDEX(' ', Name)) END AS MiddleName, RIGHT(Name, CHARINDEX(' ', REVERSE(Name))) AS LastName FROM a01_parse_test GO -- Create instead of update trigger on the view to update names separately CREATE TRIGGER tg_v_ParseNames_Update ON v_ParseNames INSTEAD OF UPDATE AS BEGIN UPDATE TGT SET Name = SRC.FirstName + (CASE WHEN LEN(SRC.MiddleName) > 0 THEN ' ' + SRC.MiddleName ELSE '' END) + ' ' + SRC.LastName FROM a01_parse_test TGT INNER JOIN INSERTED SRC ON SRC.Id = TGT.Id END GO SELECT * FROM v_ParseNames WHERE Id = 3 UPDATE v_ParseNames SET FirstName = 'Bill' WHERE Id = 3 SELECT * FROM v_ParseNames WHERE Id = 3来处理您的更新。

以下完整示例：

Id          FirstName       MiddleName      LastName
----------- --------------- --------------- ---------------
1           Barack          Hussein          Obama
2           George          Walker           Bush
3           William         Jefferson        Clinton
4           Ronald          Wilson           Reagan

所以在改变之前

UPDATE v_ParseNames SET FirstName = 'Bill' WHERE Id = 3

然后UPDATE语句可以只更新名字：

Id          FirstName       MiddleName      LastName
----------- --------------- --------------- ---------------
3           Bill            Jefferson        Clinton

然后在更新语句运行之后：

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Answer 2

被修改 您可以直接在UPDATE语句中使用这些函数（每this）。假设您的表格中有Name，FirstName，MiddleName和LastName列：

UPDATE a01_parse_test
SET FirstName=LEFT(Name, CHARINDEX(' ', Name)), 
    MiddleName=CASE WHEN CHARINDEX(' ', Name) <> LEN(Name) - CHARINDEX(' ', REVERSE(Name)) + 1 THEN 
        SUBSTRING(Name, CHARINDEX(' ', Name)+ 1, LEN(Name) - CHARINDEX(' ', REVERSE(Name))-CHARINDEX(' ', Name)) END, 
    LastName=RIGHT( Name, CHARINDEX(' ', REVERSE(Name)))

如果您的表格中不存在这些列，则您需要使用ALTER TABLE添加这些列：

ALTER TABLE a01_parse_test
ADD FirstName VARCHAR(50) NULL, 
    MiddleName VARCHAR(50) NULL, 
    LastName VARCHAR(50) NULL

通过使用SELECT的命令更新表

2 个答案: