从ruby中的字符串中的每一行中删除尾随空格

Question

任何人都可以帮助我，如何删除ruby中字符串中每行的尾随空格....例如：

str = "Hello everyone. \nHope you guys are doing good  \nstrange i can't remove this spaces"

我试过rstrip，但它不适合我....可能要尝试gsub ....我希望答案是在下面的方式。

"Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces"

Answer 1

str.split("\n").map(&:rstrip).join("\n")

它可能与正则表达式有关，但我更喜欢这种方式。

Answer 2

您可以使用gsub!来修改接收器：

str = "Hello everyone. \nHope you guys are doing good  \nstrange i can't remove this spaces"
str.gsub!(/\s\n/, "\n").inspect
#=> "Hello everyone.\nHope you guys are doing good \nstrange i can't remove this spaces"

Answer 3

使用gsub的另一个人：

str.gsub(/\s+$/, '')
#=> "Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces"

/\s+$/在换行符之前匹配一个或多个空格（\s+）（$）

Answer 4

或者像这样

str.each_line.map(&:strip).join("\n")
#=> "Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces"