Question

有没有办法在异常命中并退出程序之前降低异常以执行其余的try语句？

while(True):
    try:
        do something 1
        error occurs here
        do something 2
    except error as e:
         if(iteration == 2):
             iteration += 1
             # here I want to go back to do something 2 instead of exit()
         exit()

Answer 1

The try statement：

如果finally存在，则指定'cleanup'处理程序。执行try子句，包括任何except和else子句。如果任何子句中发生异常但未处理，则会临时保存该异常。 finally子句被执行。如果存在已保存的异常，则会在finally子句的末尾重新引发异常。如果finally子句引发另一个异常或执行return或break语句，则丢弃保存的异常：

def f():
    try:
        1/0
    finally:
        return 42

>>> f()
42

Answer 2

您的代码格式有点偏差。请尝试以下

iteration = 0

while True:
    try:
        print(a) # this will cause an error since a isn't defined
    except Exception as e:
        print(str(e)) # this will tell you what the error is
        iteration += 1
        if iteration <= 2:
            iteration += 1
            print(iteration) # just to check if code works , you can remove later
            # here I want to go back to do something 2 instead of exit()
        else:
            exit()

这将运行代码两次，因此if iteration <= 2会在iteration == 3时退出。

Answer 3

检查特定异常以查看第一个函数是否导致错误或设置标志：

flag = False
while True:
    try:
        do something 1
        error occurs here
        flag = True
        do something 2
    except error as e:
         if not flag:
            do something 
            exit()
    flag  = False

如果do something 1导致错误，则该标志仍然为False，如果是第二个，则该标志将设置为True。

如果只有第一个可以出错，那么只需在{except>中的do something 2：

while True:
    try:
        do something 1
        error occurs here
        do something 2
    except error as e:
            do something 2
            exit()

手动降低python

3 个答案: