Question

我有这个案子：

[Serializable]
public class FormBuscarCorteReligacaoViewModel
{
    public CorteReligacao CorteReligacao { get; set; }
}

[Serializable]
public class OrdensFinalizadasViewModel : FormBuscarCorteReligacaoViewModel
{
    public Manutencao Manutencao { get; set; }
    public DateTime? DataInicio { get; set; }
    public DateTime? DataFim { get; set; }

    public OrdensFinalizadasViewModel()
    {
    }
}

所以这里的孩子是OrdensFinalizadasViewModel。我有这个：

@model ProjetoPath.OrdensFinalizadasViewModel

@using (Html.BeginForm("Buscar", "OrdensFinalizadas", FormMethod.Post, new { id = "FormBuscarOrdensFinalizadas" }))
{
    @Html.Partial("~/Views/Shared/_FormBusca.cshtml", Model)
}

我的控制员：

    [HttpPost]
    public ActionResult Buscar(OrdensFinalizadasViewModel modelOrdensFinalizadas)
    {
        //DO STUFF
    }

我想要的是能够访问CorteReligacao FormBuscarCorteReligacaoViewModel。但它只填充了OrdensFinalizadasViewModel属性。

我的观点~/Views/Shared/_FormBusca.cshtml：

@using Capgemini.Telemetria.STCortes.Domain.ViewModel.Common
@model Capgemini.Telemetria.STCortes.Domain.ViewModel.Common.FormBuscarCorteReligacaoViewModel

@{
    var modelOrdensFinalizadas = Model as ProjectPath.OrdensFinalizadasViewModel;
}

<table class="tabela_filtro" style="border: 1px solid #ccc; margin-bottom: 5px; font-size: 11px" />
<thead>
 [...]
</thead>
<tbody>
    @if(modelOrdensFinalizadas != null)
    {
        <tr>
            <td>
                <label>
                    Data
                </label>
            </td>
            <td>
                @Html.TextBoxFor(model => modelOrdensFinalizadas.DataInicio, new { id = "dataInicio", @class = "campoData", @placeholder = "Data Inicio" })
            </td>
            [...]
        </tr>
    }
    <tr>
        <td>
            <label class="label_filtro">
                CP
            </label>
        </td>
        <td>
            @Html.EditorFor(model => model.CorteReligacao.CoreCp, new { style = "width: 20px;" })
            <span class="validation-message">@Html.ValidationMessageFor(model => model.CorteReligacao.CoreCp)</span>
        </td>
        [...]
            <input type="image" src="~/Content/img/icons/enviar.gif" value="Buscar" title="Buscar" />
        </td>
    </tr>
</tbody>

有可能吗？我在asp.net MVC上有点新鲜。非常感谢任何帮助/消化。

此致

Answer 1

在您的视图中，您告诉它您的模型是FormBuscarCorteReligacaoViewModel类型。如果您将其更改为

@using Capgemini.Telemetria.STCortes.Domain.ViewModel.Common
@model Capgemini.Telemetria.STCortes.Domain.ViewModel.Common.OrdensFinalizadasViewModel

并删除此部分

@{
    var modelOrdensFinalizadas = Model as ProjectPath.OrdensFinalizadasViewModel;
}

你应该可以使用

@Html.EditorFor(model => model.CorteReligacao.CoreCp, new { style = "width: 20px;" })

您需要将文本框更改为

@Html.TextBoxFor(model => model.DataInicio, new { id = "dataInicio", @class = "campoData", @placeholder = "Data Inicio" })

您是否尝试在模型中添加构造函数以初始化子属性？

[Serializable]
public class FormBuscarCorteReligacaoViewModel
{
    public FormBuscarCorteReligacaoViewModel()
    {
        CorteReligacao = new CorteReligacao();
    }
    public CorteReligacao CorteReligacao { get; set; }
}

[Serializable]
public class OrdensFinalizadasViewModel : FormBuscarCorteReligacaoViewModel
{
    public Manutencao Manutencao { get; set; }
    public DateTime? DataInicio { get; set; }
    public DateTime? DataFim { get; set; }

    public OrdensFinalizadasViewModel()
        : base()
    {
        Manutencao = new Manutencao();
    }
}

Answer 2

是的可能，我建议你做一些改变

第一：从部分视图中删除

titleLabel

将此部分更改为您的视图并将其从部分删除，将modelOrdensFinalizadas重命名为Model，

         @{
         var modelOrdensFinalizadas = Model as          ProjectPath.OrdensFinalizadasViewModel;
       }

然后在您的局部视图中，只需将表格的其余部分放入

      <table class="tabela_filtro" style="border: 1px solid #ccc; margin-bottom: 5px; font-size: 11px" />
       <thead>

        [...]

     </thead>
    <tbody>
         @if(Model!= null)
         {
    <tr>
        <td>
            <label>
                Data
            </label>
        </td>
        <td>
            @Html.TextBoxFor(model => Model.DataInicio, new  { id = "dataInicio", @class = "campoData", @placeholder = "Data Inicio" })
        </td>
        [...]
    </tr>
}
<tr>
     //here your partial view
     @Html.Partial("~/Views/Shared/_FormBusca.cshtml", Model)
          </tr>
  </tbody>

现在在您的控制器中，您将可以访问模型（OrdensFinalizadasViewModel和FormBuscarCorteReligacaoViewModel）

你在控制器中变为空，因为

    <td>
        <label class="label_filtro">
            CP
        </label>
    </td>
    <td>
        @Html.EditorFor(model => model.CorteReligacao.CoreCp, new { style = "width: 20px;" })
        <span class="validation-message">@Html.ValidationMessageFor(model => model.CorteReligacao.CoreCp)</span>
    </td>
    [...]
        <input type="image" src="~/Content/img/icons/enviar.gif" value="Buscar" title="Buscar" />
    </td>

不是部分视图中模型（FormBuscarCorteReligacaoViewModel）的一部分

希望这可以帮助你或者至少给你一个想法

Begin form不提交继承的viewmodel ASP.NET MVC4

2 个答案: