Question

我有一个看起来像的SQL表：

email               User_id Category
Sarah.Ackland@bmo.com   44  Sent_Emails
Sarah.Ackland@bmo.com   44  Sent_Emails
Sarah.Ackland@bmo.com   44  Undeliverable
Adam.Bus@wraglaw.com    50  Sent_Emails
Adam.Duthie@bevn.com    56      Sent_Emails

我正在寻找一个看起来像的输出：

email               User_id Category
Adam.Bushby@wraglaw.com 50  Sent_Emails
Adam.Duthie@bevn.com    56      Sent_Emails

主要是我不希望看到任何被标记为“未送达”的电子邮件。我尝试使用distinct，但仍然给了我一行“Sarah.Ackland@bmo.com”

Appreciate your support.

Thanks

Answer 1

我想你想要这样的东西：

select t.*
from sqltable t
where not exists (select 1
                  from sqltable t2
                  where t2.email = t.email and t2.category = 'Undeliverable'
                 );

Answer 2

试试这个sql语句：

SELECT * FROM your_table WHERE User_id NOT IN (SELECT User_id FROM your_table WHERE Category = 'Undeliverable')

Answer 3

SELECT DISTINCT * 
FROM your_table 
WHERE User_id NOT IN (SELECT User_id FROM your_table WHERE Category = 'Undeliverable')

SQL独特的问题

3 个答案: