Question

我的Sql代码是这样的：

DELIMITER $$

CREATE FUNCTION `get_theme`(`section_type` VARCHAR(50))
RETURNS VARCHAR(50)
CONTAINS SQL
SQL SECURITY DEFINER

BEGIN

DECLARE name,dirname VARCHAR(50) ;
SELECT a.name INTO name , a.dirname INTO dirname FROM themes as a
INNER JOIN sections as b ON 
a.section_id = b.id 
WHERE b.name = 'administrators' AND a.`status` = 'Y';

RETURN name + '#' + dirname;
END $$

DELIMITER ;

当我在heidiSQL 9.2.0.4961中执行此代码时，我收到此错误：未定义变量：a

但是当我执行这段代码时：

 SELECT a.name as name , a.dirname as dirname FROM themes as a
 INNER JOIN sections as b ON 
 a.section_id = b.id 
 WHERE b.name = 'administrators' AND a.`status` = 'Y';

没有问题，它完全正常。

我的代码出了什么问题？任何想法？

Answer 1

您使用的语法错误。正确的语法是：

SELECT list_of_expressions INTO list_of_variables FROM ...

替换此片段：

SELECT a.name INTO name , a.dirname INTO dirname FROM themes as a

这一个：

SELECT a.name, a.dirname INTO name , dirname FROM themes as a

一句话：不要分配与表中列相同的变量，例如：DECLARE name,dirname，如果要在查询中稍后使用它们，则会导致混淆和错误。为变量使用前缀，例如：DECLARE v_name,v_dirname

定义INNER JOIN表时MySQL存储函数语法错误

1 个答案: