我有一个名为table_listnames的表,其结构如下所示
mysql> desc table_listnames;
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(255) | NO | | NULL | |
+-------+--------------+------+-----+---------+----------------+
2 rows in set (0.04 sec)
它有样本数据,如图所示
mysql> select * from table_listnames;
+----+------------+
| id | name |
+----+------------+
| 6 | WWW |
| 7 | WWWwww |
| 8 | WWWwwws |
| 9 | WWWwwwsSSS |
| 10 | asdsda |
+----+------------+
5 rows in set (0.00 sec)
我有一个要求,如果在表格下找不到名字,我需要插入或者什么都不做
我是这样实现的
String sql = "INSERT INTO table_listnames (name) SELECT name FROM (SELECT ?) AS tmp WHERE NOT EXISTS (SELECT name FROM table_listnames WHERE name = ?) LIMIT 1";
pst = dbConnection.prepareStatement(sql);
pst.setString(1, salesName);
pst.setString(2, salesName);
pst.executeUpdate();
在这种情况下是否可以知道给定名称的记录的id