Question

不久之前我试图在bootstrap-select lib上写一个小片段，它应该打开并隐藏一些关于父选项的点击/更改事件的额外选项（在底部示例中为一半）。

应如何运作......

当用户点击特定选项时，一些包含更多附加信息的额外项目将显示在父项下方。当用户再次单击时，应隐藏额外的项目，并从已选择的选项中清除子项目。

有什么问题？

不幸的是我的jquery水平并不高，所以在这一刻我只有/显示/没有/隐藏/子项目和清除选择的功能（如果选择了某个隐藏父项的子项）。如果父项目上的选中箭头不显示，那么将会很好，仅限于孩子。

我的例子

这是我的短代码 -

＆＃13;

    $('.remove-example').find('.hider').hide();

  $('.selectpicker').change(function() {

      var feta = $(this).find("option:selected:first").attr('id');
      var feta1 = $(this).find("option:selected:last").attr('id');
      
      $('.remove-example').find('.' + feta).show();
      $('.remove-example').find('.' + feta1).show();
      
    $('.remove-example').selectpicker('refresh');

  });




$('.rm-mustard').click(function() {
    $('.remove-example').find('.Mustard').hide();
    $('.remove-example').selectpicker('refresh');
  });
  $('.rm-mustard1').click(function() {
    $('.remove-example').find('.Mustard').show();
    $('.remove-example').selectpicker('refresh');
  });


 $('.selectpicker').selectpicker();

＆＃13;

.btn-primary {
  padding: 0px 74px;
  margin-top: 5px;
}                
#tastes {
  margin: 15px 0px 0px 15px;
}

.padd {
 margin-left:20px;   
}
}

＆＃13;

<script src="http://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.js"></script>
<script src="http://cdnjs.cloudflare.com/ajax/libs/bootstrap-select/1.6.3/js/bootstrap-select.js"></script>
<script src="http://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.2/js/bootstrap.js"></script>

<link href="http://cdnjs.cloudflare.com/ajax/libs/bootstrap-select/1.6.3/css/bootstrap-select.css" rel="stylesheet"/>
<link href="http://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.2/css/bootstrap.css" rel="stylesheet"/>

 <select class="selectpicker remove-example" multiple>
    <option  id="Mustard" value="">Mustard</option>
     <option data-subtext="50g" class="Mustard hider padd">Mustard2</option>
     <option data-subtext="1kg" class="Mustard hider padd">Mustard3</option>
    <option id="Ketchup">Ketchup</option>
     <option data-subtext="50g" class="Ketchup hider padd">Ketchup2</option>
     <option data-subtext="1kg" class="Ketchup hider padd">Ketchup3</option>
    <option value="Relish">Relish</option>
  </select>


<button class="btn btn-success rm-mustard1">Show Mustard</button>
<button class="btn btn-warning rm-mustard">Remove again</button>

＆＃13;

http://jsfiddle.net/k0r974b7/

父母是：芥末/番茄酱

儿童是：Mustard1，Mustard2 / Ketchup1，Ketchup2

Answer 1

尝试

＆＃13;

$('.remove-example').find('.hider').hide();
$('.selectpicker').change(function() {

  var childSelector = $(this).find('option[id]:selected').map(function() {
    return '.' + this.id;
  }).get();


  var $cvisible = $(this).find('.hider').hide().filter(childSelector.join()).show();
  $(this).find('.hider').not($cvisible).prop('selected', false);
  $(this).selectpicker('refresh');

});

$('.rm-mustard').click(function() {
  $('.remove-example').find('.Mustard').hide();
  $('.remove-example').selectpicker('refresh');
});
$('.rm-mustard1').click(function() {
  $('.remove-example').find('.Mustard').show();
  $('.remove-example').selectpicker('refresh');
});

＆＃13;

.btn-primary {
  padding: 0px 74px;
  margin-top: 5px;
}
#tastes {
  margin: 15px 0px 0px 15px;
}
.padd {
  margin-left: 20px;
}

＆＃13;

<link rel="stylesheet" type="text/css" href="//cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.2/css/bootstrap.css" />
<link rel="stylesheet" type="text/css" href="//cdnjs.cloudflare.com/ajax/libs/bootstrap-select/1.6.3/css/bootstrap-select.css" />

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.2/js/bootstrap.js"></script>
<script type="text/javascript" src="//cdnjs.cloudflare.com/ajax/libs/bootstrap-select/1.6.3/js/bootstrap-select.js"></script>

<select class="selectpicker remove-example" multiple>
  <option id="Mustard" value="">Mustard</option>
  <option data-subtext="50g" class="Mustard hider padd">Mustard2</option>
  <option data-subtext="1kg" class="Mustard hider padd">Mustard3</option>
  <option id="Ketchup">Ketchup</option>
  <option data-subtext="50g" class="Ketchup hider padd">Ketchup2</option>
  <option data-subtext="1kg" class="Ketchup hider padd">Ketchup3</option>
  <option value="Relish">Relish</option>
</select>
<button class="btn btn-success rm-mustard1">Show Mustard</button>
<button class="btn btn-warning rm-mustard">Remove again</button>

＆＃13;

Answer 2

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<script type="text/javascript">
    $(document).ready(function() {
        $("#list li").click(function() {
            var selected = $(this).attr('id').toString();
            switch (selected) {
                case "listItem1":
                    element1.style.display = 'inline-block';
                    element2.style.display = 'none';
                    element3.style.display = 'none';
                    element4.style.display = 'none';

                    image1.style.display = 'inline-block';
                    image2.style.display = 'none';
                    image3.style.display = 'none';
                    image4.style.display = 'none';

                    break;
                case "listItem2":
                    element2.style.display = 'inline-block';
                    element1.style.display = 'none';
                    element3.style.display = 'none';
                    element4.style.display = 'none';

                    image2.style.display = 'inline-block';
                    image1.style.display = 'none';
                    image3.style.display = 'none';
                    image4.style.display = 'none';
                    break;
                case "listItem3":
                    element3.style.display = 'inline-block';
                    element2.style.display = 'none';
                    element1.style.display = 'none';
                    element4.style.display = 'none';

                    image3.style.display = 'inline-block';
                    image2.style.display = 'none';
                    image1.style.display = 'none';
                    image4.style.display = 'none';
                    break;
                case "listItem4":
                    element4.style.display = 'inline-block';
                    element2.style.display = 'none';
                    element1.style.display = 'none';
                    element3.style.display = 'none';

                    image4.style.display = 'inline-block';
                    image2.style.display = 'none';
                    image3.style.display = 'none';
                    image1.style.display = 'none';
                    break;
            }
        });
    });
</script>

<div id="listItems">
    <ul id="list">
        <li id="listItem1">ITEM 1</li>
        <li id="listItem2">ITEM 2</li>
        <li id="listItem3">ITEM 3</li>
        <li id="listItem4">ITEM 4</li>
    </ul>
</div>


<div id="linkedElements">
    <div id="element1" style="display: none;">ITEM 1</div>
    <div id="element2" style="display: none;">ITEM 2</div>
    <div id="element3" style="display: none;">ITEM 3</div>
    <div id="element4">ITEM 4</div>
</div>

<div id="testImages">
    <div id="linkedImages">
        <div id="image1" style="display: none;">
            <img src="images/Hydrangeas.jpg" width="10%" height="20%" />
        </div>
        <div id="image2" style="display: none;">
            <img src="images/Jellyfish.jpg" width="10%" height="20%" />
        </div>
        <div id="image3" style="display: none;">
            <img src="images/Koala.jpg" width="10%" height="20%" />
        </div>
        <div id="image4">
            <img src="images/Lighthouse.jpg" width="10%" height="20%" />
        </div>
    </div>

在bootstrap-select上显示/隐藏选项？

2 个答案: