Question

如何解决此错误：

func loginMobilephone(phone : String , password : String , withBlock block : ((result:NSDictionary , error: NSError)-> Void)!)
{
    var params : AnyObject! = ["username" :phone,"passwd": password, "session_id" : Constant.instance().session]

    var path : String! = "/account/common/login";
    NetworkManager.sharedClient().postPath(path, parameters: params, withBlock: block)
    NetworkManager.sharedClient().postPath(<#path: String!#>, parameters: <#[NSObject : AnyObject]!#>, withBlock: <#(([NSObject : AnyObject]!, NSError!) -> Void)!##([NSObject : AnyObject]!, NSError!) -> Void#>)
}

错误是：

无法使用类型'的参数列表调用'postPath'（String！，参数：AnyObject！，withBlock :(（结果：NSDictionary，错误： NSError） - ＆gt;空隙）！）'

或如何将其转换为Swift：

+(void)loginMobilephone:(NSString *)phone password:(NSString *)password withBlock:(void (^)(NSDictionary *, NSError *))block{
    NSDictionary *params = @{@"username" : phone,
                             @"passwd" : password,
                             @"session_id":[[Constant instance] session]
                             };
    [[NetworkManager sharedClient] postPath:APIUSERLOGIN parameters:params withBlock:block]; }

Answer 1

params应该是字典[NSObject：AnyObject]而不是AnyObject！。

试试这样：

let params: [NSObject : AnyObject] = ["username" : phone, "passwd" : password, "session_id" : Constant.instance().session]

并将方法参数更改为此

func loginMobilephone(phone: String, password: String, withBlock block: ((result: [NSObject : AnyObject] , error: NSError)-> Void) ) {
    // ... code
}

如何将objc NSDictionary转换为Swift

1 个答案: