Question

我已经看过并阅读了一些关于此的问题，但我无法弄清楚发生了什么。我有一个插入到表中的SP然后只返回一个带有最后一个插入id的列（因为我正在执行多个语句lastInsertID（）不起作用。

CREATE DEFINER=`graffixnyc`@`%` PROCEDURE `createUser`(
IN userName VARCHAR(50),
IN firstName VARCHAR(25),
IN lastName VARCHAR(25),
IN pass text)
BEGIN
SELECT FLOOR(RAND() * 0xFFFFFFFF) into @salt;
INSERT INTO `users` (`username`, `first_name`,`last_name`,`salt`,`password`)
VALUES (userName, firstName,lastName, (select
@salt),sha2(concat(md5(pass(select @salt)),256));
SELECT LAST_INSERT_ID()  as lastinsert;

END

现在当我执行它时，MySql将返回最后插入记录的值。当我尝试使用PHP访问它时，我得到Null。

$paramUsername = $req->params('username'); // Getting parameter with names
$paramFirstName = $req->params('firstname');
$paramLastName = $req->params('lastname');
$paramPassword = $req->params('password');
$sql = "CALL createUser(:username, :firstname,:lastname,:password)";
try {
    $dbCon = getConnection();
    $stmt = $dbCon->prepare($sql);  
    $stmt->bindParam("username", $paramUsername);
    $stmt->bindParam("firstname", $paramFirstName);
    $stmt->bindParam("lastname", $paramLastName);
    $stmt->bindParam("password", $paramPassword);
    $stmt->execute();
    $row= $stmt->fetch();
    $last_id=$row["lastinsert"];
    $user->id =$last_id;

我也尝试使用输出Paramater，如下所示：

CREATE DEFINER=`graffixnyc`@`%` PROCEDURE `createUser`(
IN userName VARCHAR(50),
IN firstName VARCHAR(25),
IN lastName VARCHAR(25),
IN pass text,
OUT lastinsert INT)
BEGIN
SELECT FLOOR(RAND() * 0xFFFFFFFF) into @salt;
INSERT INTO `users` (`username`, `first_name`,`last_name`,`salt`,`password`)
VALUES (userName, firstName,lastName, (select
@salt),sha2(concat(md5(pass(select @salt)),256));
SET lastinsert=(SELECT LAST_INSERT_ID());
SELECT lastinsert;

END

$paramUsername = $req->params('username'); 
$paramFirstName = $req->params('firstname');
$paramLastName = $req->params('lastname');
$paramPassword = $req->params('password');
$sql = "CALL createUser(:username, :firstname,:lastname,:password,
@lastinsert)";

try {
    $dbCon = getConnection();
    $stmt = $dbCon->prepare($sql);  
    $stmt->bindParam("username", $paramUsername);
    $stmt->bindParam("firstname", $paramFirstName);
    $stmt->bindParam("lastname", $paramLastName);
    $stmt->bindParam("password", $paramPassword);
    $stmt->execute();
    $row = $dbCon->query("select @lastinsert;")>fetch();
    $last_id=$row["@lastinsert"];
    $user->id =$last_id;

当我这样尝试时，我收到了这个错误：

{"error":{"text":SQLSTATE[HY000]: General error: 2014 Cannot execute queries
while other unbuffered queries are active. Consider using
PDOStatement::fetchAll(). Alternatively, if your code is only ever going to
run against mysql, you may enable query buffering by setting the
PDO::MYSQL_ATTR_USE_BUFFERED_QUERY attribute.}}

所以我尝试了FetchAll并得到了同样的错误..然后我尝试了这个，我在这里发现它有效，但因为它只返回1行1场，看起来我真的不需要循环通过任何东西：< / p>

$stmt->execute();
$stmt = $dbCon->prepare("select @lastinsert;");  
$outputArray = $dbCon->query("select @lastinsert;")->fetchAll();
foreach($outputArray as $row)
{
    $last_id=$row["@lastinsert"];
}

那么，如果有更好的方法来做到这一点？我确定有。我是PHP和mySQL的新手，但对SQLServer有很多经验，所以任何见解都会受到赞赏。

Answer 1

我想通了..这很好用，我不需要输入参数或循环：

SP：

CREATE DEFINER=`graffixnyc`@`%` PROCEDURE `createUser`(
IN userName VARCHAR(50),
IN firstName VARCHAR(25),
IN lastName VARCHAR(25),
IN pass text)
BEGIN
SELECT FLOOR(RAND() * 0xFFFFFFFF) into @salt;
INSERT INTO `users` (`username`, `first_name`,
`last_name`,`salt`,`password`)
VALUES (userName, firstName,lastName, (select @salt),sha2(concat(md5(pass
),(select @salt)),256));
SELECT LAST_INSERT_ID()as lastinsert;

END

PHP：

$paramUsername = $req->params('username'); 
$paramFirstName = $req->params('firstname');
$paramLastName = $req->params('lastname');
$paramPassword = $req->params('password');
$sql = "CALL createUser(:username, :firstname,:lastname,:password)";
try {
    $dbCon = getConnection();
    $stmt = $dbCon->prepare($sql);  
    $stmt->bindParam("username", $paramUsername);
    $stmt->bindParam("firstname", $paramFirstName);
    $stmt->bindParam("lastname", $paramLastName);
    $stmt->bindParam("password", $paramPassword);
    $stmt->execute();
    $user->id =$stmt->fetchColumn(0);
    $dbCon = null;

PHP从存储过程返回输出

1 个答案: