Question

我想使用URI或CGI库来获取此url的查询部分的路径。换句话说，只是：'/ scouting / amateur'。这是可能的还是我需要使用正则表达式？

http://10.241.180.63:3149/login?redirect_path=http%3A%2F%2F10.241.180.63%3A3149%2Fscouting%2Famateur

Answer 1

使用Ruby内置函数建议（如果设计方法，您可能希望实现一些错误处理）。

require 'uri'

query = URI("http://10.241.180.63:3149/login?redirect_path=http%3A%2F%2F10.241.180.63%3A3149%2Fscouting%2Famateur").query

path = URI(URI.decode(query).split('=')[1]).path

您可能会发现gem uri-query_params有用/更优雅（它会自动解码查询参数）。 E.g。

require 'uri/query_params'

uri = URI("http://10.241.180.63:3149/login?redirect_path=http%3A%2F%2F10.241.180.63%3A3149%2Fscouting%2Famateur")

URI(uri.query_params["redirect_path"]).path

Answer 2

试试这个 -

url = URI.parse('http:://10.241.180.63:3149/login?redirect_path=http%3A%2F%2F10.241.180.63%3A3149%2Fscouting%2Famateur')

redirect_path = u.opaque.split("redirect_path=").last
# redirect_path is now {"redirect_path"=>["http://10.241.180.63:3149/scouting/amateur"]}

result = redirect_path.split("/").last(2).join("/")
# result = 'scouting/amateur'

解码重定向网址 - Ruby on Rails

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