Question

你可以像这样使用sprintf：

$query = '
        SELECT a.id, a.name, a.sort_code, a.account_number, a.swift_code, %a
        FROM hr_employees_bank a
        LEFT JOIN hr_employees b ON b.id = a.employee
        %d
        WHERE a.employee = :id
        AND b.admin = :admin_id 
        ';

$query = sprintf($query, 'c.name as account_status', 'LEFT JOIN crm_bank_account_statuses c ON a.account_status = c.id');

我在查询的这一部分出现了MySQL语法错误：

%a FROM hr_employees_bank a LEFT JOIN hr_employees b ON b.id = a.employee

此致

Answer 1

简而言之，不，你不能像这样使用sprintf，你应该看一下sprintf的文档：

http://php.net/sprintf

％a不代表类型说明符，这就是它在您的查询中输出的原因。

％d将参数视为整数，并且您正在传递字符串。

正确使用sprintf，您的代码应如下所示：

$query = '
    SELECT a.id, a.name, a.sort_code, a.account_number, a.swift_code, %s
    FROM hr_employees_bank a
    LEFT JOIN hr_employees b ON b.id = a.employee
    %s
    WHERE a.employee = :id
    AND b.admin = :admin_id 
    ';

$query = sprintf($query, 'c.name as account_status', 'LEFT JOIN crm_bank_account_statuses c ON a.account_status = c.id');

sprintf在我的查询中返回0

1 个答案: