我想从Service函数返回数据并通过routeProvider将其注入控制器,但只有在数据完全加载后才会注入。
app.js:
.when('/sources', {
templateUrl: 'views/app/source/inventory.html',
controller: 'InventoryCtrl',
pageTitle: 'Data Inventory',
resolve: {
orders: function (OrderService) {
return OrderService.getOrders();
},
sources: function (SourceService) {
return SourceService.getSources();
}
}
})
SourceService:
angular.module('wp.source')
.factory('SourceService', function ($http, $q) {
return {
getSources: function () {
var model = {
sources: []
};
var promises = [];
return $http.get('datasets/project.json')
.then(function (data) {
if(localStorage['files'] != null) {
var files = JSON.parse(localStorage['files']);
for (var i = 0; i < files.length; i++) {
model.sources.push(files[i]);
}
}
var sources = [];
for (var sourceId in data.data.sources) {
var source = data.data.sources[sourceId];
source.id = sourceId;
sources.push(source);
}
angular.forEach(sources, function (source) {
promises.push($http.get('datasets/' + source.filename).then(function (datasource, resolve) {
var metadata = datasource.data.metadata;
var source = {
name: metadata.name,
address: metadata.url,
frequency: metadata.refresh,
type: metadata.type,
tags: metadata.tags,
size: metadata.size,
active: source.active,
sourceID: source.id,
sourceFile: source.filename
};
return source;
}));
});
//var finalPromise = sources.reduce(function (promise, source, index, array) {
// return promise.then(function (a) {
// var query = $http.get('datasets/' + source.filename)
// .then(function (datasource) {
// var metadata = datasource.data.metadata;
// model.sources.push({
// name: metadata.name,
// address: metadata.url,
// frequency: metadata.refresh,
// type: metadata.type,
// tags: metadata.tags,
// size: metadata.size,
// active: source.active,
// sourceID: source.id,
// sourceFile: source.filename
// });
// });
// });
//}, $q.when([]));
//
//finalPromise.finally(function () {
// return model;
//})
$q.all(function () {
return model;
});
});
}
}
});
控制器:
angular.module('wp.source')
.controller('InventoryCtrl', function ($scope, orders, sources) {
$scope.orders = orders.data;
$scope.gridView = true;
$scope.rowView = false;
$scope.allSources = sources.sources;
$scope.shownSources = $scope.allSources;
...
目前我遇到的问题是在“model”完全加载之前注入了值。我试图将子查询打包成$ q.all的承诺,但我不确切地知道去哪里
任何帮助将不胜感激
答案 0 :(得分:0)
您想使用$ q.defer()并返回延迟的promise对象。 您的代码看起来像这样。
angular.module('wp.source')
.factory('SourceService', function ($http, $q) {
return {
getSources: function () {
var model = {
sources: []
};
var deffered = $q.defer();
var promises = [];
return $http.get('datasets/project.json')
.then(function (data) {
if(localStorage['files'] != null) {
var files = JSON.parse(localStorage['files']);
for (var i = 0; i < files.length; i++) {
model.sources.push(files[i]);
}
}
var sources = [];
for (var sourceId in data.data.sources) {
var source = data.data.sources[sourceId];
source.id = sourceId;
sources.push(source);
}
angular.forEach(sources, function (source) {
promises.push($http.get('datasets/' + source.filename).then(function (datasource, resolve) {
var metadata = datasource.data.metadata;
var source = {
name: metadata.name,
address: metadata.url,
frequency: metadata.refresh,
type: metadata.type,
tags: metadata.tags,
size: metadata.size,
active: source.active,
sourceID: source.id,
sourceFile: source.filename
};
return source;
}));
});
//var finalPromise = sources.reduce(function (promise, source, index, array) {
// return promise.then(function (a) {
// var query = $http.get('datasets/' + source.filename)
// .then(function (datasource) {
// var metadata = datasource.data.metadata;
// model.sources.push({
// name: metadata.name,
// address: metadata.url,
// frequency: metadata.refresh,
// type: metadata.type,
// tags: metadata.tags,
// size: metadata.size,
// active: source.active,
// sourceID: source.id,
// sourceFile: source.filename
// });
// });
// });
//}, $q.when([]));
//
//finalPromise.finally(function () {
// return model;
//})
$q.all(promises).then(function () {
deferred.resolve(model);
});
});
}
return deferred.promise();
}
});
编辑正如其他人提到的那样,您需要将您的承诺数组传递到$ q.all才能使其正常工作。另外值得注意的是,$ q.all将按照它们在promise数组中的顺序返回一个数组,其中包含每个promise的结果。
Here's a plunker demoing the use of defer
Angular's Docs中有更多$ q.defer和$ q.all。
答案 1 :(得分:0)
您需要将$q.all
与promises数组一起使用,并从外部promise中返回:
angular.module('wp.source')
.factory('SourceService', function($http, $q) {
return {
getSources: function() {
var model = {
sources: []
};
return $http.get('datasets/project.json').then(function(data) {
if (localStorage['files'] != null) {
var files = JSON.parse(localStorage['files']);
for (var i = 0; i < files.length; i++) {
model.sources.push(files[i]);
}
}
var sources = [],
promises = [];
for (var sourceId in data.data.sources) {
var source = data.data.sources[sourceId];
source.id = sourceId;
sources.push(source);
}
var promises = sources.map(function(source) {
return $http.get('datasets/' + source.filename).then(function(datasource, resolve) {
var metadata = datasource.data.metadata;
model.sources.push({
name: metadata.name,
address: metadata.url,
frequency: metadata.refresh,
type: metadata.type,
tags: metadata.tags,
size: metadata.size,
active: source.active,
sourceID: source.id,
sourceFile: source.filename
});
});
});
return $q.all(promises).then(function() {
return model;
});
});
}
}
});
答案 2 :(得分:0)
您没有正确使用$q.all
。对代码的最简单修复方法是更改
$q.all(function () {
return model;
});
到
$q.all(promises).then(function() {
return model;
});
你基本上没有&#34;告诉&#34;承诺需要汇总的$q.all
。请参阅documentation for $q并查看all
的工作原理。