Question

我想在批处理文件中使用PowerShell命令发送电子邮件。为此，我实现了一个名为 sendMail 的函数。我这样称呼它：

setlocal enabledelayedexpansion
call:sendMail
powershell -command "!_mailCommand!"
endlocal
pause&goto:eof

我的 sendMail 功能：

:sendMail

set "_mailCommand=&{$filenameAndPath = '!resultFile!';"
set "_mailCommand=%_mailCommand%$SMTPMessage = New-Object System.Net.Mail.MailMessage('%_mailFrom%', '%_mailTo%', '%_mailSubject%', '%_mailBody%');"
set "_mailCommand=%_mailCommand%$attachment = New-Object System.Net.Mail.Attachment($filenameAndPath);"
set "_mailCommand=%_mailCommand%$SMTPMessage.Attachments.Add($attachment);"
set "_mailCommand=%_mailCommand%$SMTPClient = New-Object Net.Mail.SmtpClient('%_mailHost%', %_mailPort%);"
set "_mailCommand=%_mailCommand%$SMTPClient.EnableSsl = $true;"
set "_mailCommand=%_mailCommand%$SMTPClient.Credentials = New-Object System.Net.NetworkCredential('%_mailFrom%','%_mailSenderPassword%');"
set "_mailCommand=%_mailCommand%$SMTPClient.Send($SMTPMessage)}"
echo %_mailSenderPassword%

出乎意料的是我得到了这样的输出：

12345Aa！

异常呼叫＆＃34;发送＆＃34;用＆＃34; 1＆＃34;参数：＆＃34;发送邮件失败。＆＃34;

在行：1字符：499   ... m＆＃39;，＆＃39; 12345Aa ^＆＃39;）; $ SMTPClient.Send（$ SMTPMessage）}

CategoryInfo：NotSpecified：（:) []，MethodInvocationException

FullyQualifiedErrorId：SmtpException

您可以猜到，我的密码是 12345Aa！，我在代码的开头定义为set "_mailSenderPassword=12345Aa^^!"

那我错过了什么？提前谢谢！

Answer 1

当您使用延迟扩展时，您应该避免扩展百分比，否则您会遇到插入符号^和感叹号!以及有时也带引号的问题。

在扩展百分比之后，内容将被解析为特殊字符，但在延迟扩展后，它将保持不变。

setlocal EnableDelayedExpansion
set "_mailSenderPassword=12345Aa^!"
call :sendMail
powershell -command "!_mailCommand!"
exit /b

:sendMail
set "_mailCommand=&{$filenameAndPath = '!resultFile!';"
set "_mailCommand=!_mailCommand!$SMTPMessage = New-Object System.Net.Mail.MailMessage('!_mailFrom!', '!_mailTo!', '!_mailSubject!', '!_mailBody!');"
set "_mailCommand=!_mailCommand!$attachment = New-Object System.Net.Mail.Attachment($filenameAndPath);"
set "_mailCommand=!_mailCommand!$SMTPMessage.Attachments.Add($attachment);"
set "_mailCommand=!_mailCommand!$SMTPClient = New-Object Net.Mail.SmtpClient('!_mailHost!', !_mailPort!);"
set "_mailCommand=!_mailCommand!$SMTPClient.EnableSsl = $true;"
set "_mailCommand=!_mailCommand!$SMTPClient.Credentials = New-Object System.Net.NetworkCredential('!_mailFrom!','!_mailSenderPassword!');"
set "_mailCommand=!_mailCommand!$SMTPClient.Send($SMTPMessage)}"
echo !_mailSenderPassword!
exit /b

Answer 2

以下简化示例适用于我（它成功回显了12345Aa^!）：

set "_mailSenderPassword=12345Aa^!"

setlocal enabledelayedexpansion
call:sendMail
powershell -command "!_mailCommand!"
endlocal
pause&goto:eof

:sendMail
set "_mailCommand=echo '%_mailSenderPassword%';"
echo %_mailSenderPassword%
echo %_mailCommand%

请注意，我必须在之前设置_mailSenderPassword 我致电setlocal enabledelayedexpansion。

还有一个有趣的怪癖：在enabledelayedexpansion下你仍然可以获得相同的结果，但你必须使用3个（三个）插入符号。例如。以下内容将起作用：

setlocal enabledelayedexpansion set "_mailSenderPassword=12345Aa^^^!" call:sendMail powershell -command "!_mailCommand!" endlocal pause&goto:eof :sendMail set "_mailCommand=echo '%_mailSenderPassword%';" echo %_mailSenderPassword% echo %_mailCommand%

转义序列问题 - 批量

2 个答案: