我有两个属性。我需要针对显示兼容值的相当大的矩阵验证这些属性。
示例属性:
public string firstValue { get; set; }
public string lastValue { get; set; }
样本矩阵:
A B C
A X O O
B O X X
C X O X
让x轴代表" firstValue" y轴代表" lastValue"。该程序必须验证由" X"表示的无效组合。向用户抛出错误。
样本验证:
if (firstValue == "A")
{
if (lastValue == "A" || lastValue =="C)
Console.WriteLine("Invalid Combination");
}
显然可以使用if \ else和switch逻辑以多种方式重构,但是当你向矩阵添加数百个值时,它开始变得可怕。我决定在矩阵中创建一个每行包含一个函数的新类。
public class MutuallyExclusiveValidation
{
public void CheckA(string lastValue)
{
if (lastValue == "A" || lastValue == "C")
{
Console.WriteLine("Invalid Combination");
}
}
public void CheckB(string lastValue)
{
if (lastValue == "B")
{
Console.WriteLine("Invalid Combination");
}
}
public void CheckC(string lastValue)
{
if (lastValue == "B" || lastValue == "C")
{
Console.WriteLine("Invalid Combination");
}
}
}
然后我设计了这样的东西,以确保我没有达到比我需要更多的代码。谓词将返回布尔选择并调用需要运行的验证方法。 (只是一个样本,而不是生产代码)
public static void CheckForMutuallyExclusiveValues(string firstValue, string lastvalue)
{
var allValidators = GetMutuallyExclusiveValidators(firstValue, lastvalue);
var requiredValidators = allValidators.First(x => x.Key(firstValue));
var validationClassInstance = new MutuallyExclusiveValidation();
requiredValidators.Value(validationClassInstance);
}
public static Dictionary<Predicate<string>, Action<MutuallyExclusiveValidation>> GetMutuallyExclusiveValidators(string firstValue, string lastvalue)
{
var returnDictionary = new Dictionary<Predicate<string>, Action<MutuallyExclusiveValidation>>();
Action<MutuallyExclusiveValidation> validation;
Predicate<string> condition;
validation = x => x.CheckA(lastvalue);
condition = x => x == "A";
returnDictionary.Add(condition, validation);
validation = x => x.CheckB(lastvalue);
condition = (x => x == "B");
returnDictionary.Add(condition, validation);
validation = x => x.CheckC(lastvalue);
condition = (x => x == "C");
returnDictionary.Add(condition, validation);
return returnDictionary;
}
这似乎很有效,但我无法帮助您思考更好的方法。有什么想法吗?
编辑:Fabjan的回答是我为这个特殊问题而回答的问题。还要感谢Tim Schmelter。答案 0 :(得分:3)
使用某种方法创建一个二维数组并使用它来验证记录,如:
class MyClass
{
bool[,] matrix = new bool[,]
{
{false, true, false}, // x1 y123
{true, false, true}, // x2 y123
{true, false, false}, // x3 y123
};
string[] xValues = { "A", "B", "C" };
string[] yValues = { "A", "B", "C" };
public bool IsValid(string value1, string value2)
{
return matrix[Array.IndexOf(xValues, value1), Array.IndexOf(yValues, value2)];
}
}
class Program
{
static void Main()
{
MyClass c = new MyClass();
Console.WriteLine(c.IsValid("A", "A"));
Console.WriteLine(c.IsValid("B", "C"));
Console.WriteLine(c.IsValid("A", "C"));
Console.ReadKey();
}
}
输出:
答案 1 :(得分:3)
您可以使用Dictionary<string, HashSet<string>>
将X值存储为关键字,将所有无效的Y值存储为值。
Dictionary<string, HashSet<string>> InvalidValues = new Dictionary<string, HashSet<string>> {
{"A", new HashSet<string>{"A", "C"}},
{"B", new HashSet<string>{"B"}},
{"C", new HashSet<string>{"B", "C"}}
};
现在,如果给定的x值和y值无效,您可以有效地检查:
var emptySet = new HashSet<string>();
var invalidValues = allValues
.Where(x => InvalidValues.TryGet(x.FirstValue, emptySet).Contains(x.LastValue));
foreach (Value val in invalidValues)
Console.WriteLine("Invalid Combination: {0}|{1}", val.FirstValue, val.LastValue);
使用此扩展来linqify Dictionary.TryGetValue
:
public static TValue TryGet<TKey, TValue>(this Dictionary<TKey, TValue> dict, TKey key, TValue defaultValue = default(TValue))
{
TValue value;
bool success = dict.TryGetValue(key, out value);
if (success)
return value;
else
return defaultValue;
}
这堂课:
public class Value
{
public string FirstValue { get; set; }
public string LastValue { get; set; }
}
和一些样本值:
var allValues = new List<Value> {
new Value { FirstValue = "A", LastValue = "C" },
new Value { FirstValue = "A", LastValue = "B" },
new Value { FirstValue = "B", LastValue = "C" },
new Value { FirstValue = "A", LastValue = "A" }
};