Question

使用此脚本时：

DECLARE @FORDERBZV2     varchar(20)
DECLARE @FORDERBZV          varchar(20)

SELECT  @FORDERBZV      = (SELECT TOP 1 [FOR] FROM [Mil].[dbo].[FXO] where FOR like 'T0%' order by FOR desc)

--[FOR] is declared as varchar(20)  
SELECT  @FORDERBZV2 = right (@FORDERBZV, 19) + 1

--and after i run
insert into [Mil].[dbo].[FEO]
Values (@FORDERBZV2,....)

我收到此错误：

Msg 245，Level 16，State 1，Line 6
将varchar值'T000005571'转换为数据类型int。
时转换失败

我不明白为什么，因为所有文件都声明为VARCHAR（20）：

FOR from [Mil].[dbo].[FXO] = VARCHAR(20)
@FORDERBZV  =  VARCHAR(20)
@FORDERBZV  =  VARCHAR(20)

此外，该脚本将正常运行一次，但当我尝试再次运行它时，我收到错误。

Answer 1

所以，问题出在这个代码行：SELECT @FORDERBZV2 = right (@FORDERBZV, 19) + 1 你得到错误的原因是你的字符串实际上不是20个字符长，但它更短，所以right函数只返回整个字符串。

我假设您希望通过零填充连续数字得到字母T，所以您应该做这样的事情：

DECLARE @FORDERBZV2     varchar(20)
DECLARE @FORDERBZV          varchar(20)

SELECT  @FORDERBZV      = (SELECT TOP 1 [FOR] 
                           FROM [Mil].[dbo].[FXO] 
                           WHERE [FOR] 
                           LIKE 'T0%' 
                           ORDER BY [FOR] DESC)

SELECT  @FORDERBZV2 = 'T' + RIGHT(
                            REPLICATE('0', LEN(@FORDERBZV)-1) + 
                            CAST (
                            CAST(RIGHT(@FORDERBZV, LEN(@FORDERBZV)-1) AS int) + 1 
                            AS varchar(20))
                            , LEN(@FORDERBZV)-1)

insert into [Mil].[dbo].[FEO]
Values (@FORDERBZV2,....)

see fiddle here.

将varchar值'A0001'转换为数据类型int时转换失败

1 个答案: