我有一个txt文件: gcc-4.7.2.txt:写入数据: 你好 这是一个测试文件。 谢谢 :压缩为gcc-4.7.2.tar.bz2
现在,我运行以下代码:
#include <sstream>
#include <fstream>
#include <iostream>
#include <boost/iostreams/filtering_streambuf.hpp>
#include <boost/iostreams/copy.hpp>
#include <boost/iostreams/filter/bzip2.hpp>
#include <boost/filesystem.hpp>
int main()
{
using namespace std;
using namespace boost::iostreams;
char filename[] = "gcc-4.7.2.tar.bz2";
if (!boost::filesystem::exists(filename))
{
cout << "Can't find " << filename << ". Expect errors to follow! " << endl;
}
ifstream file(filename, ios_base::in | ios_base::binary);
filtering_streambuf<input> in;
filtering_streambuf<output> out;
in.push(bzip2_decompressor());
in.push(file);
try
{
//cout << "in_file:" << in << endl;
boost::iostreams::copy(in, cout);
//boost::iostreams::copy(in, out);
//cout << cout << endl;
//boost::iostreams::copy(in, compressed_string);
//cout << "Copied" << compressed_string << " " << in.str() << endl;
}
catch (const bzip2_error& exception)
{
cout << "catchblock" << endl;
cout << exception.what() << endl;
int error = exception.error();
if (error == bzip2::data_error)
{
cout << "compressed data stream is corrupted";
}
else if (error == bzip2::data_error_magic)
{
cout << "compressed data stream does not begin with the 'magic' sequence 'B' 'Z' 'h'";
}
else if (error == bzip2::config_error)
{
cout << "libbzip2 has been improperly configured for the current platform";
}
else
{
cout << "Error: " << error;
}
cout << endl;
}
}
运行时输出为:
dev4@sun-desktop:~/readerwriter$ ./test1
gcc-4.7.2.txt0000644000175100001440000000004312547435102011603 0ustar dev4usersHello
This is a test file.
由于
Hello之前有哪些字符? 为什么打印文件名?
我只是使用boost :: iostream函数将in-stream'in'复制到cout中。
为什么只能将它复制到'cout'如何在那里有一个不同的命名输出流?
答案 0 :(得分:1)
如果解压缩压缩的tar存档,则会获得tar存档!
此处描述了tar存档格式:https://en.wikipedia.org/wiki/Tar_(computing)#File_format
要说明其工作原理,请尝试以下方法:
dev4@sun-desktop:~/readerwriter$ ./test1 | tar x
提取文件