Question

这是我的数据库结果

Array ([0] => Array ( [shopname] => Shop name [fueltype] => Pertol [amount] => 1000 ) 
       [1] => Array ( [shopname] => dfsdfsd [fueltype] => Pertol [amount] => 54456 )
       [2] => Array ( [shopname] => dfsdfsd [fueltype] => Disel [amount] => 54456 )
)

我需要像

这样的结果

[["Shop name", "Pertol", 1000],["dfsdfsd", "Pertol", 54456],["Shop name", "Disel", 54456]]

怎么这样，我不知道？

Answer 1

$mapped = array_map('array_values', $input_array); // apply filter so we dont get the keys
$json = json_encode($mapped);

Answer 2

array_map()以及array_values()将适合您： -

<?php
$array = Array ( '0' => Array ( 'shopname' => 'Shop name','fueltype' => 'Pertol','amount' => 1000 ), 
        '1' => Array ( 'shopname' => 'dfsdfsd' ,'fueltype' => 'Pertol','amount' => 54456 ),
        '2' => Array ( 'shopname' => 'dfsdfsd','fueltype' => 'Disel','amount' => 54456 )
);


$values_data_only = array_map('array_values', $array);
$desire_result = json_encode($values_data_only);
echo $desire_result;

?>

输出： - https://eval.in/395344

同样可以通过简单的foreach()： -

<?php
$array = Array ( '0' => Array ( 'shopname' => 'Shop name','fueltype' => 'Pertol','amount' => 1000 ), 
        '1' => Array ( 'shopname' => 'dfsdfsd' ,'fueltype' => 'Pertol','amount' => 54456 ),
        '2' => Array ( 'shopname' => 'dfsdfsd','fueltype' => 'Disel','amount' => 54456 )
);

$new_array = array();

foreach ($array as $k=> $arr){
    $new_array[$k][] = $arr['shopname'];
    $new_array[$k][] = $arr['fueltype'];
    $new_array[$k][] = $arr['amount'];
}
echo "<pre/>";print_r($new_array);
$desired_result_2 = json_encode($new_array);
echo $desired_result_2;
?>

输出： - https://eval.in/395354

Answer 3

试试：

$input  = array( /* your input data */ );
$output = array();

foreach ($input as $data) {
  $output[] = array_values($data);
}

从php中的数组中删除键值

3 个答案: