Question

将此视为我之前问题的延伸：
How to pass a member function pointer to an overloaded method in a template function?

我有一个函数接收指向类方法的指针：

template<typename Return, typename T>
T ReceiveFuncPtr (Return (T::*Method)(const int&))
{
  T obj;
  (obj.*Method)(1);
  return obj;
}

works fine用于手写类，例如：

template<typename X, typename = void>
struct A
{
  std::pair<X,bool> foo (const X& i) { return std::pair<X,bool>(X(),true); } // choice
  void foo (std::initializer_list<X> i) { return 0; } 
};

int main ()
{
  ReceiveFuncPtr(&A<int>::foo); // OK
}

但是，我无法通过std::set<int>::insert(const int&)

ReceiveFuncPtr(&std::set<int>::insert);

以上陈述结果如下：

error: no matching function for call to ‘ReceiveFuncPtr(<unresolved overloaded function type>)’
   ReceiveFuncPtr(&std::set<int>::insert); // ERROR
                                        ^   
note: candidate: template<class Return, class T> T ReceiveFuncPtr(Return (T::*)(const int&))
 T ReceiveFuncPtr (Return (T::*Method)(const int&))
   ^   
note:   template argument deduction/substitution failed:
note:   mismatched types ‘const int&’ and ‘std::initializer_list<int>’
   ReceiveFuncPtr(&std::set<int>::insert); // ERROR
                                        ^
note:   mismatched types ‘const int&’ and ‘std::set<int>::const_iterator {aka std::_Rb_tree_const_iterator<int>}’
note:   mismatched types ‘const int&’ and ‘std::set<int>::const_iterator {aka std::_Rb_tree_const_iterator<int>}’
note:   mismatched types ‘const int&’ and ‘std::set<int>::value_type&& {aka int&&}’
note:   couldn't deduce template parameter ‘Return’

通过这种方法的正确方法是什么？

将成员函数指针传递给重载的类方法到模板函数中

0 个答案: