Question

有人可以解释为什么我收到错误“无法分配类型[CLLocationCoordinate2D]的不可变值”我会给出两个场景。我希望第二个工作的原因是因为我将处于循环中并且需要每次都将它传递给drawShape函数。

此代码有效：

func drawShape() {
    var coordinates = [
        CLLocationCoordinate2D(latitude: 40.96156150486786, longitude: -100.24319656647276),
        CLLocationCoordinate2D(latitude: 40.96456685906742, longitude: -100.25021235388704),
        CLLocationCoordinate2D(latitude: 40.96528813790064, longitude: -100.25022315443493),
        CLLocationCoordinate2D(latitude: 40.96570116316434, longitude: -100.24954721762333),
        CLLocationCoordinate2D(latitude: 40.96553915028926, longitude: -100.24721925915219),
        CLLocationCoordinate2D(latitude: 40.96540144388564, longitude: -100.24319644831121),
        CLLocationCoordinate2D(latitude: 40.96156150486786, longitude: -100.24319656647276),
    ]
    var shape = MGLPolygon(coordinates: &coordinates, count: UInt(coordinates.count))
    mapView.addAnnotation(shape)
}

此代码不起作用：

override func viewDidLoad() {
    super.viewDidLoad()

    // does stuff
    var coords: [CLLocationCoordinate2D] = [
            CLLocationCoordinate2D(latitude: 40.96156150486786, longitude: -100.24319656647276),
            CLLocationCoordinate2D(latitude: 40.96456685906742, longitude: -100.25021235388704),
            CLLocationCoordinate2D(latitude: 40.96528813790064, longitude: -100.25022315443493),
            CLLocationCoordinate2D(latitude: 40.96570116316434, longitude: -100.24954721762333),
            CLLocationCoordinate2D(latitude: 40.96553915028926, longitude: -100.24721925915219),
            CLLocationCoordinate2D(latitude: 40.96540144388564, longitude: -100.24319644831121),
            CLLocationCoordinate2D(latitude: 40.96156150486786, longitude: -100.24319656647276),
        ]

    self.drawShape(coords)
}

func drawShape(coords: [CLLocationCoordinate2D]) {
    var shape = MGLPolygon(coordinates: &coords, count: UInt(coords.count)) //---this is where the error shows up
    mapView.addAnnotation(shape)
}

我不明白为什么这不起作用。我甚至println(coordinates) vs println(coords)，它为每个人提供了相同的输出。

Answer 1

将参数传递给函数时，默认情况下它们将作为不可变传递。就像你将它们声明为let一样。

当您将coords param传递给MGPolygon方法时，它会作为inout参数传递，这意味着这些值可以更改，但因为默认情况下参数是不可变值，编译器抱怨。

您可以通过明确告诉编译器可以通过在var前添加前缀来修改此参数来修复它。

func drawShape(var coords: [CLLocationCoordinate2D]) {
    var shape = MGLPolygon(coordinates: &coords, count: UInt(coords.count)) 
    mapView.addAnnotation(shape)
}

使用var前缀参数意味着您可以在函数中改变该值。

编辑：Swift 2.2

请改为使用关键字inout。

func drawShape(inout coords: [CLLocationCoordinate2D]) {
    var shape = MGLPolygon(coordinates: &coords, count: UInt(coords.count)) 
    mapView.addAnnotation(shape)
}

Swift无法分配类型[CLLocationCoordinate2D]的不可变值

1 个答案: