Question

我有一个对象数组如下：

var GOM = [{name:"Kuroko",ability:"misdirection"},
           {name:"Kise",ability:"perfect copy"},
           {name: "Akashi", ability: "emperor's eye"}];

是否可以使用lodash中的某些预定义函数或本机javascript（不是forEach）将其拆分为2个数组。

["Kuroko","Kise","Akashi"] and ["misdirection","perfect copy","emperor's eye"]

我知道我可以这样做：

var names = [];
var abilities = [];
GOM.forEach(function(member){
  names.push(member.name);
  abilities.push(member.ability);
});

但我正在寻找另一种方式。

Answer 1

将map()，values()和unzip()合并到一个包装器中：

var wrapper = _(GOM).map(_.values).unzip();

然后很容易抓住名字：

wrapper.first()
// → [ "Kuroko", "Kise", "Akashi" ]

和能力：

wrapper.last()
// → [ "misdirection", "perfect copy", "emperor's eye" ]

Answer 2

Array.map()适用于此：

＆＃13;

var GOM = [{name:"Kuroko",ability:"misdirection"},{name:"Kise",ability:"perfect copy"},{name: "Akashi", ability: "emperor's eye"}];

var names = GOM.map(function(item) {
  return item.name;
});
var abilities = GOM.map(function(item) {
  return item.ability;
});
alert(names + '\n' + abilities);

＆＃13;

Answer 3

你拥有的代码很好，但是如果你正在寻找更多的东西，那就是功能性的，＆＃34;始终reduce：

var GOM = [ { name: "Kuroko", ability: "misdirection" },
            { name: "Kise", ability: "perfect copy" },
            { name: "Akashi", ability: "emperor's eye" } ];

var result = GOM.reduce(function(memo, member) {
  memo.names.push(member.name);
  memo.abilities.push(member.ability);
  return memo;
}, { names: [], abilities: [] });

console.log(result.names);
// => [ "Kuroko", "Kise", "Akashi" ]

console.log(result.abilities);
// => [ "misdirection", "perfect copy", "emperor's eye" ]

Answer 4

看起来没有什么比Lodash中的两个短片更短：

var data = [
  {name:"Kuroko",ability:"misdirection"},
  {name:"Kise",ability:"perfect copy"},
  {name: "Akashi", ability: "emperor's eye"}
];

var names = _.pluck(data, 'name');
var abilities = _.pluck(data, 'ability');

alert(JSON.stringify(names, null, 4));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/3.10.0/lodash.js"></script>

如何将一个对象数组拆分成多个普通数组，其中每个数组都由一个属性的值填充？

4 个答案: