我的应用程序运行url http://localhost:81/ip_update/00178r时出现错误ValueError:View函数没有返回响应。 我无法解决,如果有人能帮助我,我将非常感激
def ip_update (client):
ip = request.remote_addr
if 'r' in client:
customer = cliente.rstrip ('r')
urllib2.urlopen ('http://localhost:85/administration/ip_update/' + client + '/' + ip)
time.sleep (3)
else:
server = 'localhost'
port = 3306
login = root
password = 'password'
mdb.connect con = (host = server, port = port = user login, passwd = password, use_unicode = True)
cur = con.cursor ()
cur.execute ("SELECT FROM tar_cliente ebas.tarefa WHERE tar_status = 'processing' and tar_cliente = '" + client $
if cur.rowcount == 0:
Data2 data = ()
server = data2 ['clients'] [customer] ['server']
urllib2.urlopen ('http://' + server + '/administration/ip_update/' + client + '/' + ip)
time.sleep (3)
return 'request for ip received for updating client code' + client
else:
return 'denied updating, client operation underway'
答案 0 :(得分:2)
当None
测试为真时,您的函数返回if
:
if 'r' in client:
customer = cliente.rstrip ('r')
urllib2.urlopen ('http: // localhost: 85 / administration / ip_update /' + client + '/' + ip)
time.sleep (3)
在这种情况下你也需要回复一个回复。在这里使用睡眠毫无意义;你所做的就是推迟向浏览器返回内容。