我退出了应用程序,重新启动它,我得到了例外。
public void onCreate() {
-->here Parse.initialize(this, "adfsfasdfs",
"asdfadfsdf");
ParseInstallation.getCurrentInstallation().saveInBackground();
ParseInstallation.create(identity == null ? "No Identity Set"
: identity);
异常
07-08 23:27:29.411: E/AndroidRuntime(4889): Caused by: java.lang.IllegalStateException: ParsePlugins is already initialized
07-08 23:27:29.411: E/AndroidRuntime(4889): at com.parse.ParsePlugins.set(ParsePlugins.java:27)
07-08 23:27:29.411: E/AndroidRuntime(4889): at com.parse.ParsePlugins.access$200(ParsePlugins.java:11)
07-08 23:27:29.411: E/AndroidRuntime(4889): at com.parse.ParsePlugins$Android.initialize(ParsePlugins.java:141)
07-08 23:27:29.411: E/AndroidRuntime(4889): at com.parse.Parse.initialize(Parse.java:178)
07-08 23:27:29.411: E/AndroidRuntime(4889): at com.mcruiseon.caregiri.Registration.onCreate(Registration.java:98)
清单文件
<service android:name="com.parse.PushService" />
<receiver android:name="com.parse.ParseBroadcastReceiver" >
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
<action android:name="android.intent.action.USER_PRESENT" />
</intent-filter>
</receiver>
<receiver
android:name="com.parse.ParsePushBroadcastReceiver"
android:exported="false" >
<intent-filter>
<action android:name="com.parse.push.intent.RECEIVE" />
<action android:name="com.parse.push.intent.DELETE" />
<action android:name="com.parse.push.intent.OPEN" />
</intent-filter>
</receiver>
编辑:
我想知道为什么Parse会为此抛出异常。为什么不只是info
继续前进。它的初始化,如果我再次初始化它是如此重要。
解决方案
我放弃了Parse。不喜欢应用方式,只是为了刺激维护。
答案 0 :(得分:28)
Parse.initialize()
只应为整个应用程序调用 一次 。
在Activity
的{{1}}函数中调用它可以使其多次初始化,因为可以在应用的生命周期内多次创建一个Activity
相反,请创建应用程序类(并在应用程序的清单中添加onCreate
属性)。
申请:(注意不是活动/服务/接收者)
android:name
<强> AndroidManifest:强>
//Note that this is an android.app.Application class.
public class MyApplication extends android.app.Application {
@Override
public void onCreate() {
super.onCreate();
//This will only be called once in your app's entire lifecycle.
Parse.initialize(this,
getResources().getString(R.string.parse_application_id),
getResources().getString(R.string.parse_client_key));
}
答案 1 :(得分:4)
NEVERMIND,我已经修好了。问题是由于语法错误。感谢大家的解决方案。
这很奇怪,因为我已经按照给出了什么,但现在我根本没有得到任何推送通知?我所做的唯一改变是:
清单
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme"
android:name="full.package.name.UseParse" >
申请类
public class UseParse extends android.app.Application {
@Override
public void onCreate() {
super.onCreate();
Parse.initialize(this, "id", "key");
ParseInstallation.getCurrentInstallation().saveInBackground();
}
答案 2 :(得分:2)
自己检查初始化并只处理异常,错误不会导致应用程序崩溃,只是悄悄地抛出异常。
try {
Parse.initialize(this);
parseinited = true;
}
catch (IllegalStateException e) {
e.printStackTrace();
}
答案 3 :(得分:1)
我使用boolean isParseInitialized 变量.Works解决方向更改,即在同一个应用程序会话中重新创建活动时。代码段:
public class YourActivity extends Activity {
private static boolean isParseInitialized = false;
public static final String APPLICATION_ID = "your_application_id";
public static final String CLIENT_KEY = "your_client_key";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_youractivity);
if(isParseInitialized==false) {
Parse.initialize(this, APPLICATION_ID, CLIENT_KEY);
isParseInitialized = true;
}
..........
}
答案 4 :(得分:0)
这是一个解决方案
public class MainActivity extends AppCompatActivity {
static boolean parseIsInit = false;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
if (!parseIsInit){
Log.d("demo",""+parseIsInit );
Parse.initialize(this, "PutHereYourKeys", "PutHereYourKeys");
parseIsInit=true;
}
ParseInstallation.getCurrentInstallation().saveInBackground();
}
}