Question

我有以下课程：

class Base {
    static $static_var = 'base_static';
    public static function static_init() {
        // HERE, I want to get the caller extended class.
        echo __CLASS__.'<br/>';
        // HERE, I want to get the caller extended static variable.
        echo static::$static_var.'<br/>';
        // Do some initialization works depends on the static_var.
        // ...
    }
};

class Children extends Base {
    // overridden
    static $static_var = 'extended_static';
};

// Call Now
Children::static_init();

/** echos:
Base
base_static
*/

/** I want to export:
Children
extended_static
*/

我可以将Base类扩展为许多子类。

所以在我的子类中，我可以通过自己的静态变量来定义静态参数。

有没有办法这样做？或者我应该如何设计课程？

Answer 1

我认为你要找的是＆＃39; get_called_class（）＆＃39;，根据get_called_class（）的php.net定义：

＆＃34;获取调用静态方法的类的名称。＆＃34;

所以结束代码就像：

class Base {
  static $static_var = 'base_static';
  public static function static_init() {
    $caller_class = get_called_class();
    // HERE, I want to get the caller extended class.
    echo $caller_class . '<br/>';
    // HERE, I want to get the caller extended static variable.
    echo $caller_class::$static_var.'<br/>';
    // Do some initialization works depends on the static_var.
    // ...
  }
};

http://php.net/manual/en/function.get-called-class.php

PHP：在基类静态方法中获取调用者子类

1 个答案: