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Question

我尝试了count和distinct的所有组合（正确的:)除外）以获得以下示例。

输入：表t1

NAME       |  FOOD
Mary       |  Apple
Mary       |  Banana
Mary       |  Apple
Mary       |  Strawberry
John       |  Cherries

预期产出：

 NAME      |  FOOD
Mary       |  3
John       |  1

N.B。玛丽有两排Apple，但她有3，因为我们在列中有3个不同的值。 我只为她获得了FOOD专栏4，但我需要3 :(

Answer 1

select a.name as NAME, a.count(name) as Food 
from 
(SELECT distinct NAME,Food from table)a

Answer 2

从查询开始，该查询为您提供 NAME 和 FOOD 的独特组合：

SELECT DISTINCT t1.NAME, t1.FOOD
FROM t1

然后，您可以将其用作另一个子查询，您可以GROUP BY和Count：

SELECT sub.NAME, Count(*) AS [FOOD]
FROM
    (
        SELECT DISTINCT t1.NAME, t1.FOOD
        FROM t1
    ) AS sub
GROUP BY sub.NAME;

Answer 3

select a.name, sum(a.FoodCount) from(
select distinct name,COUNT(food) as FoodCount from #t1 group by name, food ) as a group by a.name order by 2 desc